The probability of getting \(k\) heads when flipping \(n\) coins is: \[P(E)={n\choose k}p^k(1-p)^{n-k}\]
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strongdady 2020-04-07 16:24 原文
The probability of getting \(k\) heads when flipping \(n\) coins is: \[P(E)={n\choose k}p^k(1-p)^{n-k}\]
testa23β