The probability of getting \(k\) heads when flipping \(n\) coins is:
\[P(E)={n\choose k}p^k(1-p)^{n-k}\]
testa23β
strongdady 2020-04-07 16:24 原文
The probability of getting \(k\) heads when flipping \(n\) coins is:
\[P(E)={n\choose k}p^k(1-p)^{n-k}\]
testa23β