var xhr = new XMLHttpRequest(); xhr.open('POST', 'http://localhost:8080/login'); xhr.send(null); xhr.onload = function(e) { var xhr = e.target; console.log(xhr.responseText); } 测试网站:http://www.jszg.edu.cn/portal/home/index
jiyang2018 2019-08-14 10:26 原文
var xhr = new XMLHttpRequest(); xhr.open('POST', 'http://localhost:8080/login'); xhr.send(null); xhr.onload = function(e) { var xhr = e.target; console.log(xhr.responseText); } 测试网站:http://www.jszg.edu.cn/portal/home/index