首页 > 技术文章 > 拓扑排序(DFS实现)

mmmelodyyy 2021-03-08 22:11 原文

~~~c++

#include<bits/stdc++.h>
using namespace std;

int n,m;
int graph[110][110];
int vis[110];
int ans[110],t;

bool dfs(int u){
vis[u] = -1;
for(int i = 1; i <= n; i++){
if(graph[u][i]){
if(vis[i] < 0) return false;
if(vis[i] == 0 && !dfs(i)){
return false;
}
}
}
vis[u] = 1;
ans[t++] = u;
return true;
}
int main() {
while(cin>>n>>m){
if(n == 0 && m == 0) break;
memset(graph,0,sizeof(graph));
memset(vis,0,sizeof(vis));
t = 0;
int u,v;
for(int i = 0; i < m; i++){
cin>>u>>v;
graph[u][v] = 1;
}
bool flag = true;
for(int i = 1; i <= n; i++){
if(vis[i] == 0){
if(!dfs(i)){
flag = false;
break;
}
}
}
for(int i = n -1; i >=0; i--){
if(i != n - 1) cout<<" ";
cout<<ans[i];
}
cout<<endl;
}
return 0;
}

~~~

> uva10305

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