首页 > 技术文章 > HDU-4665 Unshuffle 搜索 | 2-SAT

zhsl 2013-08-10 00:25 原文

  题目链接:http://acm.hdu.edu.cn/showproblem.php?pid=4665

  本题的2-SAT建图颇为复杂,有时间再来填坑(自己写的一直挂着,标程建图太复杂了)。。。然后用暴力搜索,用一个栈保存第一个序列就可以了,因为题目是SPG,并且重复的最多只有四个,所以搜索很好过。。

 1 //STATUS:C++_AC_62MS_276KB
 2 #include <functional>
 3 #include <algorithm>
 4 #include <iostream>
 5 //#include <ext/rope>
 6 #include <fstream>
 7 #include <sstream>
 8 #include <iomanip>
 9 #include <numeric>
10 #include <cstring>
11 #include <cassert>
12 #include <cstdio>
13 #include <string>
14 #include <vector>
15 #include <bitset>
16 #include <queue>
17 #include <stack>
18 #include <cmath>
19 #include <ctime>
20 #include <list>
21 #include <set>
22 #include <map>
23 using namespace std;
24 //#pragma comment(linker,"/STACK:102400000,102400000")
25 //using namespace __gnu_cxx;
26 //define
27 #define pii pair<int,int>
28 #define mem(a,b) memset(a,b,sizeof(a))
29 #define lson l,mid,rt<<1
30 #define rson mid+1,r,rt<<1|1
31 #define PI acos(-1.0)
32 //typedef
33 typedef __int64 LL;
34 typedef unsigned __int64 ULL;
35 //const
36 const int N=2010;
37 const int INF=0x3f3f3f3f;
38 const int MOD= 1000000007,STA=8000010;
39 const LL LNF=1LL<<55;
40 const double EPS=1e-9;
41 const double OO=1e30;
42 const int dx[4]={-1,0,1,0};
43 const int dy[4]={0,1,0,-1};
44 const int day[13]={0,31,28,31,30,31,30,31,31,30,31,30,31};
45 //Daily Use ...
46 inline int sign(double x){return (x>EPS)-(x<-EPS);}
47 template<class T> T gcd(T a,T b){return b?gcd(b,a%b):a;}
48 template<class T> T lcm(T a,T b){return a/gcd(a,b)*b;}
49 template<class T> inline T lcm(T a,T b,T d){return a/d*b;}
50 template<class T> inline T Min(T a,T b){return a<b?a:b;}
51 template<class T> inline T Max(T a,T b){return a>b?a:b;}
52 template<class T> inline T Min(T a,T b,T c){return min(min(a, b),c);}
53 template<class T> inline T Max(T a,T b,T c){return max(max(a, b),c);}
54 template<class T> inline T Min(T a,T b,T c,T d){return min(min(a, b),min(c,d));}
55 template<class T> inline T Max(T a,T b,T c,T d){return max(max(a, b),max(c,d));}
56 //End
57 
58 int num[N],sta[N],vis[N];
59 int T,n,top1,top2,mid;
60 
61 bool dfs(int u)
62 {
63     if(top2==mid)return true;
64     if(top1<mid){
65         vis[u]=0;
66         sta[top1++]=num[u];
67         if(dfs(u+1))return true;
68         top1--;
69     }
70     if(num[u]==sta[top2]){
71         vis[u]=1;
72         top2++;
73         if(dfs(u+1))return true;
74         vis[u]=0;
75         top2--;
76     }
77     return false;
78 }
79 
80 int main(){
81  //   freopen("in.txt","r",stdin);
82     int i,j;
83     scanf("%d",&T);
84     while(T--)
85     {
86         scanf("%d",&n);
87         mid=n>>1;
88         for(i=0;i<n;i++)
89             scanf("%d",&num[i]);
90 
91         top1=top2=0;
92         dfs(0);
93 
94         for(i=0;i<n;i++)
95             printf("%d",vis[i]);
96         putchar('\n');
97     }
98     return 0;
99 }

 

2-SAT(WA):

  1 /*   WA   */
  2 #include <functional>
  3 #include <algorithm>
  4 #include <iostream>
  5 //#include <ext/rope>
  6 #include <fstream>
  7 #include <sstream>
  8 #include <iomanip>
  9 #include <numeric>
 10 #include <cstring>
 11 #include <cassert>
 12 #include <cstdio>
 13 #include <string>
 14 #include <vector>
 15 #include <bitset>
 16 #include <queue>
 17 #include <stack>
 18 #include <cmath>
 19 #include <ctime>
 20 #include <list>
 21 #include <set>
 22 #include <map>
 23 using namespace std;
 24 //#pragma comment(linker,"/STACK:102400000,102400000")
 25 //using namespace __gnu_cxx;
 26 //define
 27 #define pii pair<int,int>
 28 #define mem(a,b) memset(a,b,sizeof(a))
 29 #define lson l,mid,rt<<1
 30 #define rson mid+1,r,rt<<1|1
 31 #define PI acos(-1.0)
 32 //typedef
 33 typedef __int64 LL;
 34 typedef unsigned __int64 ULL;
 35 //const
 36 const int N=2010;
 37 const int INF=0x3f3f3f3f;
 38 const int MOD= 1000000007,STA=8000010;
 39 const LL LNF=1LL<<55;
 40 const double EPS=1e-9;
 41 const double OO=1e30;
 42 const int dx[4]={-1,0,1,0};
 43 const int dy[4]={0,1,0,-1};
 44 const int day[13]={0,31,28,31,30,31,30,31,31,30,31,30,31};
 45 //Daily Use ...
 46 inline int sign(double x){return (x>EPS)-(x<-EPS);}
 47 template<class T> T gcd(T a,T b){return b?gcd(b,a%b):a;}
 48 template<class T> T lcm(T a,T b){return a/gcd(a,b)*b;}
 49 template<class T> inline T lcm(T a,T b,T d){return a/d*b;}
 50 template<class T> inline T Min(T a,T b){return a<b?a:b;}
 51 template<class T> inline T Max(T a,T b){return a>b?a:b;}
 52 template<class T> inline T Min(T a,T b,T c){return min(min(a, b),c);}
 53 template<class T> inline T Max(T a,T b,T c){return max(max(a, b),c);}
 54 template<class T> inline T Min(T a,T b,T c,T d){return min(min(a, b),min(c,d));}
 55 template<class T> inline T Max(T a,T b,T c,T d){return max(max(a, b),max(c,d));}
 56 //End
 57 
 58 struct Edge{
 59     int u,v;
 60 }e[N<<4];
 61 
 62 int first[N<<1],next[N<<4],vis[N<<1],S[N<<1];
 63 int num[N];
 64 int T,n,mt,cnt;
 65 
 66 void adde(int a,int b)
 67 {
 68     e[mt].u=a,e[mt].v=b;
 69     next[mt]=first[a];first[a]=mt++;
 70 }
 71 
 72 int dfs(int u)
 73 {
 74     if(vis[u^1])return 0;
 75     if(vis[u])return 1;
 76     int i;
 77     vis[u]=1;
 78     S[cnt++]=u;
 79     for(i=first[u];i!=-1;i=next[i]){
 80         if(!dfs(e[i].v))return 0;
 81     }
 82     return 1;
 83 }
 84 
 85 int Twosat()
 86 {
 87     int i,j;
 88     for(i=0;i<n;i+=2){
 89         if(vis[i] || vis[i^1])continue;
 90         cnt=0;
 91         if(!dfs(i)){
 92             while(cnt)vis[S[--cnt]]=0;
 93             if(!dfs(i^1))return 0;
 94         }
 95     }
 96     return 1;
 97 }
 98 
 99 int cnt2[N],tot[N],w[N][4];
100 void Init()
101 {
102     int i,j,t;
103     mt=0;mem(vis,0);
104     mem(first,-1);
105     mem(tot,0);
106     for(i=0;i<n;i++)w[num[i]][tot[num[i]]++]=i;
107     mem(cnt2,0);
108     for(i=0;i<n;i++){
109         t=num[i];
110         cnt2[t]++;
111         if(cnt2[t]==1){
112             adde((i<<1)^1,i<<1);
113             adde(i<<1,(w[t][tot[t]-1]<<1)^1);
114             adde(w[t][tot[t]-1]<<1,(i<<1)^1);
115             if(tot[t]==4){
116                 for(j=w[t][1]+1;j<n;j++){
117                     if(w[num[j]][1]==j && w[num[j]][0]<j && w[num[j]][0]>i){
118                         adde(i<<1,(w[t][1]<<1)^1);
119                         break;
120                     }
121                 }
122             }
123         }
124         else if(cnt2[t]==3){
125             adde(w[t][1]<<1,(w[t][2]<<1)^1);
126             adde((w[t][1]<<1)^1,w[t][2]<<1);
127             adde(w[t][2]<<1,(w[t][1]<<1)^1);
128             adde((w[t][2]<<1)^1,w[t][1]<<1);
129         }
130     }
131 }
132 
133 int main(){
134     freopen("in.txt","r",stdin);
135     int i,j;
136     scanf("%d",&T);
137     while(T--)
138     {
139         scanf("%d",&n);
140         for(i=0;i<n;i++)
141             scanf("%d",&num[i]);
142 
143         Init();
144         n<<=1;
145         int t=Twosat();
146     //    printf("%d\n",t);
147 
148         for(i=0;i<n;i+=2)
149             printf("%d",vis[i]);
150         putchar('\n');
151     }
152     return 0;
153 }
View Code

 

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