# 1、求出1-99之间的和 sum = 0 for i in range(100): sum = sum + i print(sum)
# 2、正序排序下列列表 a = [1, 12, 16, 19, 6, 4, 2, 66, 33, 87] # 代码 len = len(a) for i in range(len): for k in range(len - i -1): if (a[len-i-1] < a[len-i-k-2]): a[len-i-k-2],a[len-i-1] = a[len-i-1],a[len-i-k-2] print(a)
# 3.请使用迭代查找一个list中最小和最大值,并返回一个tuple # -*- coding: utf-8 -*- def findMinAndMax(L): if not isinstance(L, list): raise TypeError(L + ', bad type!') if len(L) == 0: return (None, None) n = L[0] m = L[0] for i in L: if i < n: n = i if i > m: m = i return (n, m) #测试 if findMinAndMax([]) != (None, None): print('测试失败!') elif findMinAndMax([7]) != (7, 7): print('测试失败!') elif findMinAndMax([7, 1]) != (1, 7): print('测试失败!') elif findMinAndMax([7, 1, 3, 9, 5]) != (1, 9): print('测试失败!') else: print('测试成功!')
# 4.利用切片操作,实现一个trim()函数,去除字符串首尾的空格,注意不要调用str的strip()方法 # -*- coding: utf-8 -*- def trim(s): if not isinstance(s, str): raise TypeError(s + ', bad type!') for i in range(len(s)): if (s[i:i + 1] not in ' '): s = s[i:] break elif ((s[i:i + 1] == ' ') and (i == (k - 1))): s = '' break for j in range(len(s)): if j == 0: if (s[-1:] != ' '): break else: print(s[-j - 1:-j]) if (s[-j - 1:-j] != ' '): s = s[:-j] break return s # 测试: if trim('hello ') != 'hello': print('测试失败!') elif trim(' hello') != 'hello': print('测试失败!') elif trim(' hello ') != 'hello': print('测试失败!') elif trim(' hello world ') != 'hello world': print('测试失败!') elif trim('') != '': print('测试失败!') elif trim(' ') != '': print('测试失败!') else: print('测试成功!')