首页 > 技术文章 > Stream系列(六)Match方法使用

JavaWeiBianCheng 2019-11-29 12:55 原文

#java##stream##match#

条件比配

视频讲解:https://www.bilibili.com/video/av77403655/

 

EmployeeTestCase.java
package com.example.demo;

import lombok.Data;
import lombok.ToString;
import lombok.extern.log4j.Log4j2;
import org.junit.Test;

import java.util.Collection;
import java.util.Comparator;
import java.util.List;
import java.util.stream.Collectors;
import java.util.stream.LongStream;
import java.util.stream.Stream;

import static org.junit.Assert.assertEquals;
import static org.junit.Assert.assertTrue;

@Log4j2
public class EmployeeTestCase extends BaseTest{
    @Test
    public void match() {
        //列表中所有元素都比配我们的条件
        boolean isAllMatch = list.stream().allMatch(e -> e.getSalary() >=1000);
        assertTrue(isAllMatch);
        //列表中任一元素比配我们的条件
        boolean isManyMatch = list.stream().anyMatch(e -> e.getSalary() ==1500);
        assertTrue(isManyMatch);
        //列表中没有一个元素比配我们的条件
        boolean isNoneMatch2 = list.stream().noneMatch(e -> e.getSalary() > 3000);
        assertTrue(isNoneMatch2);
    }

}
BaseTest.java
package com.example.demo;

import java.util.Arrays;
import java.util.List;

public class BaseTest {
    protected static final List<Employee> list = Arrays.asList(
            new Employee(1, "Alex", 1000),
            new Employee(2, "Michael", 2000),
            new Employee(3, "Jack", 1500),
            new Employee(4, "Owen", 1500),
            new Employee(5, "Denny", 2000));

    protected static final List<List<Employee>> listFlat = Arrays.asList(
            Arrays.asList(new Employee(1, "Alex", 1000),
                    new Employee(2, "Michael", 2000)),
            Arrays.asList(new Employee(3, "Jack", 1500),
                    new Employee(4, "Owen", 1500)),
            Arrays.asList(new Employee(5, "Denny", 2000)));
}

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