首页 > 技术文章 > 为什么Map桶中个数超过8才转为红黑树

Esquecer 2019-08-26 17:06 原文

引自博客:https://www.cnblogs.com/linghu-java/p/10598758.html

 

Because TreeNodes are about twice the size of regular nodes, we
use them only when bins contain enough nodes to warrant use
(see TREEIFY_THRESHOLD). And when they become too small (due to
removal or resizing) they are converted back to plain bins.  In
usages with well-distributed user hashCodes, tree bins are
rarely used.  Ideally, under random hashCodes, the frequency of
nodes in bins follows a Poisson distribution
(http://en.wikipedia.org/wiki/Poisson_distribution) with a
parameter of about 0.5 on average for the default resizing
threshold of 0.75, although with a large variance because of
resizing granularity. Ignoring variance, the expected
occurrences of list size k are (exp(-0.5)*pow(0.5, k)/factorial(k)). 
The first values are:
0:    0.60653066
1:    0.30326533
2:    0.07581633
3:    0.01263606
4:    0.00157952
5:    0.00015795
6:    0.00001316
7:    0.00000094
8:    0.00000006
more: less than 1 in ten million

当hashCode离散性很好的时候,树型bin用到的概率非常小,因为数据均匀分布在每个bin中,几乎不会有bin中链表长度会达到阈值。但是在随机hashCode下,离散性可能会变差,然而JDK又不能阻止用户实现这种不好的hash算法,因此就可能导致不均匀的数据分布。不过理想情况下随机hashCode算法下所有bin中节点的分布频率会遵循泊松分布,我们可以看到,一个bin中链表长度达到8个元素的概率为0.00000006,几乎是不可能事件。所以,之所以选择8,不是拍拍屁股决定的,而是根据概率统计决定的。由此可见,发展30年的Java每一项改动和优化都是非常严谨和科学的。

 

个人理解是

当loadfactor是默认是0.5,阈值是0.75

0.5时候用泊松分布计算:

代入λ = 0.5,增大K,则计算出上面的值

所以当K等于8的时候分布率已经是极低的了,因此需要把链转红黑树(java8性质)

推荐阅读