令 x = logA, y = logB, z=log(AB) 。2x = A, 2y = B, 2z = AB, 则有 2z = AB = (2x)^(2y) = 2x(2^y) ，有z = x*2y，即 log(AB) = BlogA。
wbb2109 2016-05-29 02:08 原文
令 x = logA, y = logB, z=log(AB) 。2x = A, 2y = B, 2z = AB, 则有 2z = AB = (2x)^(2y) = 2x(2^y) ，有z = x*2y，即 log(AB) = BlogA。