模拟循环数组

void main() {
	vector<int> nums{ 1,2,3,4,5,5 };
	int n = nums.size();
	int N = 2 * n ;
	vector<int> res(N,0);
	for (int i = N; i >= 0; i--) {
		res[i % N] = nums[i % n];
	}
	for (int i = 0; i < res.size(); i++) {
		cout << res[i] << endl;
	}
	return;
}