首页 > 技术文章 > java实现mongodb的模糊查询

wueryuan 2020-08-11 11:15 原文

public Result<List<Code>> getCodes(@RequestParam(required = false) String name, @RequestHeader(required = false) HttpHeaders headers)
{

Query query = new Query();

Criteria criteria = new Criteria();
name = name.trim();
if(name.equals("") || name.equals(null)){
criteria.and("name").is(name);
}else{
Criteria name= new Criteria();
name.and("name").regex("^.*" +name+ ".*$");
Criteria value= new Criteria();
value.and("value").regex("^.*" +name+ ".*$");

criteria.orOperator(name,value);//查询条件or
}

query.addCriteria(criteria);

//根据name和code进行模糊查询
//db.getCollection('code').find({"$or":[{"code" : /GM/},{"value":/感冒/}]})

//db.getCollection('code').find({ "$or" : [ { "name" : { "$regex" : "^.*感冒.*$"}} , { "value" : { "$regex" : "^.*感冒.*$"}}]}).sort({"value":1})
List<Code> codes = mongoTemplate.find(query,Code.class, "code");

return new Result<List<Code>>("0", "查询成功", codes );
}

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