ios - Swift ios 解析 json 数据只获取选定的数据

Question

下面是我尝试提取 JSON 对象的代码。我只想要状态为 != Static 的数据并在tableView

postman response
[
    {
        "id": 249,
        "name": "aBrush your teeth",
        "desc": "Brush your teeth",
        "reward": "1.00",
        "sched": "2015-01-01T08:00:00+08:00",
        "parent": "",
        "type": "",
        "child": "",
        "occurrence": {
            "name": "once"
        },
        "status": {
            "name": "static"
        },
        "date_created": "2018-04-25T14:27:20.405928+08:00",
        "date_modified": "2018-04-26T11:56:02.030647+08:00"
    },
    {
        "id": 250,
        "name": "Brush your teeth",
        "desc": "Brush your teeth",
        "reward": "1.00",
        "sched": "2015-01-01T08:00:00+08:00",
        "parent": "",
        "type": "",
        "child": "",
        "occurrence": {
            "name": "once"
        },
        "status": {
            "name": "static"
        },
        "date_created": "2018-04-25T14:28:49.780354+08:00",
        "date_modified": "2018-04-26T11:56:05.616333+08:00"
    },
    {
        "id": 252,
        "name": "Brush your teeth",
        "desc": "Brush your teeth",
        "reward": "1.00",
        "sched": "2015-01-01T08:00:00+08:00",
        "parent": "",
        "type": "",
        "child": "",
        "occurrence": {
            "name": "once"
        },
        "status": {
            "name": "static"
        },
        "date_created": "2018-04-25T14:31:02.274405+08:00",
        "date_modified": "2018-04-26T11:59:57.676148+08:00"
    },
    {
        "id": 253,
        "name": "Brush your teeth",
        "desc": "Brush your teeth",
        "reward": "1.00",
        "sched": "2015-01-01T08:00:00+08:00",
        "parent": "",
        "type": "",
        "child": "",
        "occurrence": {
            "name": "once"
        },
        "status": {
            "name": "static"
        },
        "date_created": "2018-04-25T14:34:37.097498+08:00",
        "date_modified": "2018-04-26T09:42:24.633359+08:00"
    },
    {
        "id": 254,
        "name": "Brush your teeth",
        "desc": "Brush your teeths",
        "reward": "1.00",
        "sched": "2015-01-01T08:00:00+08:00",
        "parent": "",
        "type": "",
        "child": "",
        "occurrence": {
            "name": "once"
        },
        "status": {
            "name": "static"
        },
        "date_created": "2018-04-25T14:36:53.766088+08:00",
        "date_modified": "2018-04-26T11:56:15.757769+08:00"
    },
    {
        "id": 260,
        "name": "chorename",
        "desc": "{\n  \"questions\" : [\n    {\n      \"b\" : 2,\n      \"a\" : 1\n    },\n    {\n      \"b\" : 3,\n      \"a\" : 2\n    },\n    {\n      \"b\" : 2,\n      \"a\" : 8\n    },\n    {\n      \"b\" : 9,\n      \"a\" : 7\n    },\n    {\n      \"b\" : 3,\n      \"a\" : 6\n    }\n  ],\n  \"operation\" : \"+\"\n}",
        "reward": "1.00",
        "sched": "2018-04-19T15:54:24.657644+08:00",
        "parent": "shit",
        "type": "homework",
        "child": "",
        "occurrence": {
            "name": "once"
        },
        "status": {
            "name": "ongoing"
        },
        "date_created": "2018-04-26T10:13:42.913149+08:00",
        "date_modified": "2018-04-26T10:13:42.953485+08:00"
    }
]

获取数据的代码//这里我只想从状态名称！=“静态”的dapi获取数据并将其附加到getalldetail，它是一个var getAllDetail：[[String：Any]] = [String：Any]

func demoApi() {
            Alamofire.request("test.api", method: .get, parameters: nil, encoding: JSONEncoding.default, headers: nil).responseJSON { (response:DataResponse<Any>) in

                switch(response.result) {

                case .success(_):
                    guard let json = response.result.value as! [[String:Any]]? else{ return}

                    print("Api Response : \(json)")

                    // here i only want to get data from the dapi which status name != "static"
                    for item in json {

                        self.getAllDetail.append(item)


                    }
                    if !self.getAllDetail.isEmpty{
                        DispatchQueue.main.async {
                            self.tableView.reloadData()
                        }
                    }
                    break

                case .failure(_):
                    print("Error")
                    break

                }
            }

        }

标签： iosswiftparsing

Answer 1

只需申请filter您的回复，如下所示。

let filtered  = json.filter { (dict) -> Bool in
       guard let status : [String : String] = dict["status"] as? [String : String], let statusString = status["name"] else {
         return false
       }
      return statusString.compare("static") != .orderedSame
    }