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首页 > 解决方案 > 当我在 Python Tutor 上运行代码时，我的代码一直显示错误：“太多无法解包”。如何修复此错误？

python - 当我在 Python Tutor 上运行代码时，我的代码一直显示错误：“太多无法解包”。如何修复此错误？

问题描述

这是我的代码：

big_str = "[41.386263640000003, -81.494450689999994]\t6\t2011-08-28 19:02:28\tyay. little league world series!\n[42.531041999999999, -82.90854831]\t6\t2011-08-28 19:02:29\ti'm at holiday inn express suites & hotel roseville mi (31900 little mack ave., at masonic blvd., roseville) \n[39.992309570000003, -75.131119729999995]\t6\t2011-08-28 19:02:29\t@_tweetthis what dorm r you in?\n[54.104106119999997, 28.336019929999999]\t6\t2011-08-28 19:02:29\t@andykozik круто !!!\n[25.787949600000001, -80.132949600000003]\t5\t2011-09-03 05:40:14\tpizza rustica #ftw"

# This breaks up a string of tweets into lists
def break_into_records(big_mess):
    rows = big_mess.split('\n')
    records = []
    for row in rows:
        records.append(row.split('\t'))
    for i in range(len(records)):
        records[i][0] = records[i][0].replace(' ','').strip('[]').split(',')
    return records

# This will loop over that list, and call a draw
# every time a word pops up
# as well as give you a word count
def count_words(word, data_structure):
    count = 0
    for loc, id, time, message in data_structure:
        if word in message:
            drop_pin(loc) # we pass cords to drop pin, no work to do
            count += message.count(word)
    return count

def drawGpsPoint(x):
  y = drop_pin(x)
  return y

def drop_pin(location):
    # this function needs to map the GPS cord to an x/y
    # so it can draw
    # but it has the GPS locs.
    lat, lon = location
    lat, lon = float(lat), float(lon)
    x = 500 - ((lat + 180) * 500.0/360)
    y = 500 - ((lon + 180) * 500.0/360)
    return lat, lon

a = break_into_records(big_str)
for x in a:
  drawGpsPoint(x)
  print("All Tweets Loaded")
  r = raw_input("Enter search word: ")

每次到达 drop_pin(location) 函数中的 lat, lon 时都会显示错误。在通过该行运行之前，我是否需要先分离变量？

标签： pythonpython-2.7

解决方案

你break_into_records没有做你所期望的。第一次打电话时drop_pin(location)，您的位置是

[['41.386263640000003', '-81.494450689999994'], '6', '2011-08-28 19:02:28', 'yay. little league world series!']

请注意，我location在尝试分配之前通过打印出来确定了这一点。

“解包的值太多”错误是由于尝试将其分配给lat, long.

您可能只想返回break_into_records函数的第一部分，或者您可能只想对这些字符串的第一部分进行操作。

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