powershell - 如何使用powershell根据丢失的文件获取以前的文件

Question

我想比较我的数组列表（文件夹内每个文件的文件名）和包含丢失文件的日志文件。（例如，在文件夹内我们有 24 个文件，假设我们有 01.csv、03.csv、04.csv 和 06.csv，而缺少的文件是 02.csv 和 05.csv 我想要复制 01 .csv 或 03.csv 如果缺少的文件是 02.csv 等等）如果你有任何想法可以让它变得简单。请帮忙！这是我的脚本，到目前为止我所做的是随机获取文件夹中的可用文件以提供丢失的文件。

$folder="D:\ERM\Dump_files\Hourly\RTDEG"
$RTDEG = @("rtdeg_$RTDEG_01", "rtdeg_$RTDEG_02", "rtdeg_$RTDEG_03", 
           "rtdeg_$RTDEG_04", "rtdeg_$RTDEG_05", "rtdeg_$RTDEG_06", 
           "rtdeg_$RTDEG_07", "rtdeg_$RTDEG_08", "rtdeg_$RTDEG_09", 
           "rtdeg_$RTDEG_10", "rtdeg_$RTDEG_11", "rtdeg_$RTDEG_12", 
           "rtdeg_$RTDEG_13", "rtdeg_$RTDEG_14", 
           "rtdeg_$RTDEG_15","rtdeg_$RTDEG_16", 
           "rtdeg_$RTDEG_17", "rtdeg_$RTDEG_18", "rtdeg_$RTDEG_19", 
           "rtdeg_$RTDEG_20", "rtdeg_$RTDEG_21", "rtdeg_$RTDEG_22", 
           "rtdeg_$RTDEG_23", "rtdeg_$RTDEG_24")

 $files = Get-ChildItem $folder -recurse -Exclude "*.txt", "*.log" | 
        Where-Object {($_.CreationTime -gt (Get-Date).adddays(-4))}

 if((Get-ChildItem "D:\ERM\Dump_files\Hourly\RTDEG" -Exclude "*.txt", 
 "*.log" | Measure-Object -line).lines -ge 24){

 echo "Viola! No missing files."

 }else{

 echo "Validating the missing files."

 $files.Basename | Out-File $folder\validation.txt

 $fileRTDEG = $files | ForEach-Object { ($_.BaseName) }

 set-Content $folder\validated.txt -value "Missing"


 Compare-Object $RTDEG $fileRTDEG | select -ExpandProperty InputObject | 
 Out- File $folder\validated.txt -Append ascii

 $compare = import-csv $folder\validated.txt

 foreach($missed in $compare){

 $data = $missed.Missing

 $random = gci $folder -Exclude "*.txt", "*.log" | where {$_.psIsContainer -     
 eq $false}| Resolve-Path | Get-Random -Count 1

 Copy-Item $random -Destination $folder\$data.csv

 }}

另外我想制作一个循环来提供数组。但我不认为我做得对。这是我的代码：

  $RTDEG = @()
  for ($i = 01; $i -le 24; $i ++){
  $date = (Get-Date).adddays(-4).ToString("yyyyMMdd")
  $list = "rtdeg_" + "" + $date + "" + $i.ToString("00")
  Write-Output $RTDEG
  }

标签： powershell