spring - 点燃:选择查询返回null
问题描述
我是 ignite 的新手,我正在尝试使用 ignite 存储库获取数据,但下面的查询返回“null”。
我的存储库
@Component
@RepositoryConfig(cacheName = "UserCache")
@Repository
public interface UserRepository extends IgniteRepository<UserEntity, Long> {
@Query("select a.* from UserEntity a where a.lastname=? ")
UserEntity selectUserlastName(String plastName);
我的缓存配置为
CacheConfiguration<Long, UserEntity> lUserCacheConfig =
createCacheConfigurationStore("UserCache", UserCacheStore.class);
CacheJdbcPojoStoreFactory<Long, UserEntity> lUserJdbcStoreFactory = new
CacheJdbcPojoStoreFactory<>();
UserJdbcPojoStoreFactory<? super Long, ? super UserEntity>
lUserJdbcPojoStoreFactory = new UserJdbcPojoStoreFactory<>();
lUserJdbcStoreFactory.setDataSource(datasource);
lUserJdbcStoreFactory.setDialect(new OracleDialect());
lUserJdbcStoreFactory.setTypes(lUserJdbcPojoStoreFactory.
configJdbcContactType());
lUserCacheConfig.setCacheStoreFactory(lUserJdbcStoreFactory);
// Configure Cache..
cfg.setCacheConfiguration(lUserCacheConfig);
我的 PojoStore 如下:
public class UserJdbcPojoStoreFactory<K, V> extends
AnstractJdbcPojoStoreFactory<Long, UserEntity> {
private static final long serialVersionUID = 1L;
@Autowired
DataSource datasource;
@Override
public CacheJdbcPojoStore<Long, UserEntity> create() {
// TODO Auto-generated method stub
setDataSource(datasource);
return super.create();
}
@Override
public JdbcType configJdbcContactType() {
JdbcType jdbcContactType = new JdbcType();
jdbcContactType.setCacheName("UserCache");
jdbcContactType.setKeyType(Long.class);
jdbcContactType.setValueType(UserEntity.class);
jdbcContactType.setDatabaseTable("USER");
jdbcContactType.setDatabaseSchema("ORGNITATION");
jdbcContactType.setKeyFields(new JdbcTypeField(Types.INTEGER, "id",
Long.class, "id"));
jdbcContactType.setValueFields(
new JdbcTypeField(Types.VARCHAR, "NAME", String.class, "NAME"), //
new JdbcTypeField(Types.VARCHAR, "LASTNAME", String.class, "lastname"),
//
return jdbcContactType;
}
}
请建议..
解决方案
请检查从 ignite-spring-data 库导入的 @Query 注释并使用 SqlFieldsQuery 测试您的查询。
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