java - 无法在 child() firebase 错误中为参数“pathString”传递 null

问题描述

这是代码，当我想获取用户密钥（getPhone）时遇到问题，我无法获取空值，我是编程新手。

    LayoutInflater inflater = LayoutInflater.from(this);
    View layout_pwd = inflater.inflate(R.layout.ganti_password_layout,null);

    final MaterialEditText edtPassword = (MaterialEditText)layout_pwd.findViewById(R.id.gantiPassword);
    final MaterialEditText edtNewPassword = (MaterialEditText)layout_pwd.findViewById(R.id.gantiPasswordBaru);
    final MaterialEditText edtRepeatPassword = (MaterialEditText)layout_pwd.findViewById(R.id.gantiPasswordBaruUlang);

    alertDialog.setView(layout_pwd);

    //Button
    alertDialog.setPositiveButton("GANTI", new DialogInterface.OnClickListener() {
        @Override
        public void onClick(DialogInterface dialogInterface, int i) {
            //Ganti Password Disini
            final android.app.AlertDialog waitingDialog = new SpotsDialog(Home.this);
            waitingDialog.show();

            //cek password lama
            if(edtPassword.getText().toString().equals(Common.currentUser.getPassword()))
            {
                //Cek Password Baru dan Ulang Password
                if(edtNewPassword.getText().toString().equals(edtRepeatPassword.getText().toString()))
                {
                    Map<String,Object> passwordUpdate = new HashMap<>();
                    passwordUpdate.put("password",edtNewPassword.getText().toString());

                    //Update
                    DatabaseReference user = FirebaseDatabase.getInstance().getReference("User");
                    user.child(Common.currentUser.getPhone())
                            .updateChildren(passwordUpdate)
                            .addOnCompleteListener(new OnCompleteListener<Void>() {
                                @Override
                                public void onComplete(@NonNull Task<Void> task) {
                                    waitingDialog.dismiss();
                                    Toast.makeText(Home.this, "Password Telah Diganti", Toast.LENGTH_SHORT).show();
                                }
                            })
                            .addOnFailureListener(new OnFailureListener() {
                                @Override
                                public void onFailure(@NonNull Exception e) {
                                    Toast.makeText(Home.this, e.getMessage(), Toast.LENGTH_SHORT).show();
                                }
                            });
                }
                else
                {
                    waitingDialog.dismiss();
                    Toast.makeText(Home.this, "Pengulangan Password Tidak Sesuai", Toast.LENGTH_SHORT).show();
                }
            }
            else
            {
                waitingDialog.dismiss();
                Toast.makeText(Home.this, "Password Lama Salah", Toast.LENGTH_SHORT).show();
            }

        }
    });

这就是错误

进程：com.example.novaldi.sabilulunganlaykes，PID：15878 java.lang.NullPointerException：无法在 com.google.firebase.database.DatabaseReference.child 的 child() 中为参数“pathString”传递 null（未知来源：6 ) 在 com.example.novaldi.sabilulunganlaykes.Home$4.onClick(Home.java:259) 在 android.support.v7.app.AlertController$ButtonHandler.handleMessage(AlertController.java:162) 在 android.os.Handler.dispatchMessage (Handler.java:105) 在 android.os.Looper.loop(Looper.java:164) 在 android.app.ActivityThread.main(ActivityThread.java:6541) 在 java.lang.reflect.Method.invoke(Native Method ) 在 com.android.internal.os。Zygote$MethodAndArgsCaller.run(Zygote.java:240) 在 com.android.internal.os.ZygoteInit.main(ZygoteInit.java:767)

这是我的结构数据库数据库结构

这是我的用户类

public User(){

}

public User(String nama, String password, String kodeKeamanan) {
    Nama = nama;
    Password = password;
    IsStaff = "false";
    this.KodeKeamanan = kodeKeamanan;
}

public String getKodeKeamanan() {
    return KodeKeamanan;
}

public void setKodeKeamanan(String kodeKeamanan) {
    KodeKeamanan = kodeKeamanan;
}

public String getPhone() {
    return Phone;
}

public void setPhone(String phone) {
    Phone = phone;
}

public String getIsStaff() {
    return IsStaff;
}

public void setIsStaff(String isStaff) {
    IsStaff = isStaff;
}

public String getNama() {
    return Nama;
}

public void setNama(String nama) {
    Nama = nama;
}

public String getPassword() {
    return Password;
}

public void setPassword(String password) {
    Password = password;
}

标签： javaandroidfirebasefirebase-realtime-database

存在此问题是因为该方法Common.currentUser.getPhone()返回 null。

要修复它，只需在方法调用null之前添加简单的测试。child()

像这样：

String phone = Common.currentUser.getPhone();
if (phone != null)
    user.child(phone)
                            .updateChildren(passwordUpdate)
                            .addOnCompleteListener(new OnCompleteListener<Void>() {
                                @Override
                                public void onComplete(@NonNull Task<Void> task) {
                                    waitingDialog.dismiss();
                                    Toast.makeText(Home.this, "Password Telah Diganti", Toast.LENGTH_SHORT).show();
                                }
                            })
                            .addOnFailureListener(new OnFailureListener() {
                                @Override
                                public void onFailure(@NonNull Exception e) {
                                    Toast.makeText(Home.this, e.getMessage(), Toast.LENGTH_SHORT).show();
                                }
                            });
else {
    // do something else here
}

或者编辑getPhone()它永远不会返回的方法null

java - 无法在 child() firebase 错误中为参数“pathString”传递 null

问题描述

解决方案

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