mysql - 无法从mysql中的三个表中获取不匹配的行

Question

我无法从 mysql 的三个表中获得不匹配的行。rd 表有 3 行的venueid 88。但我的查询只返回两行。我想要的输出是：

bookingId|bookingMeetingRoomId|bookingVenueId|venueId|rdId|morningTotalGuest|shiftId|
|98       |80                  |88            |88     |80  |99              |137|
|null    |null                |null           |88     |81  |null            |130|
|null     |null                |null          |88     |82  |null            |null|



SELECT a.booking_id,a.booking_meeting_room_id,a.booking_venue_id,rd.venue_id,rd.rd_id,
      rd.rd_img_name,rd.rd_rhname, rd.rd_max_capacity,
        --  shift.shift_id,
        (
        SELECT SUM(booking_total_guest)
        FROM dv_bookings
        WHERE booking_shift_name LIKE '%morning%' AND booking_venue_id = 88 AND booking_checkin = '2018-04-06' AND a.booking_meeting_room_id=dv_bookings.booking_meeting_room_id) AS 'morning_total_guest',
        (
        SELECT SUM(booking_total_guest)
        FROM dv_bookings
        WHERE booking_shift_name LIKE '%dinner%' AND booking_venue_id = 88 AND booking_checkin = '2018-04-06' AND a.booking_meeting_room_id=dv_bookings.booking_meeting_room_id) AS 'dinner_total_guest',
        (
        SELECT SUM(booking_total_guest)
        FROM dv_bookings
        WHERE booking_shift_name LIKE '%lunch%' AND booking_venue_id = 88 AND booking_checkin = '2018-04-06' AND a.booking_meeting_room_id=dv_bookings.booking_meeting_room_id) AS 'lunch_total_guest'
        FROM dv_bookings a
        RIGHT JOIN
        (
        SELECT rd_id, rd_img_name, rd_rhname,rd_max_capacity, rd_room_size,venue_id
        FROM dv_room_details
        WHERE venue_id = 88) rd ON 
        a.booking_meeting_room_id = rd.rd_id
         AND a.booking_venue_id = 88 AND a.booking_checkin= '2018-04-06'
        right JOIN

        (
        SELECT shift_id,shift_room_id,shift_venue_id,shift_morning_start_time,shift_morning_end_time,shift_lunch_start_time,shift_lunch_end_time,shift_dinner_start_time,shift_dinner_end_time
        FROM dv_venue_shift_time_table
        WHERE shift_venue_id = 88 AND shift_day_name='Fri') shift 
        -- WHERE shift_id is null) shift
        ON rd.rd_id = shift.shift_room_id 
        -- on rd.rd_id = a.booking_meeting_room_id
        -- on shift.shift_room_id = a.booking_meeting_room_id
        -- AND a.booking_venue_id = 88 AND a.booking_checkin= '2018-04-06'
        GROUP BY a.booking_meeting_room_id;

标签： mysqlsql