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javascript - Fetch unique elements from Array of Array

问题描述

I have a Array of String array i want to fetch the unique elements from that array ignoring the case. how can i fetch Example:

List of array:

[
       ["java,C,Node,ReactJs"]
        ["c","Spring"]
        ["undefined"]
        ["asdja"]
        ["Java","Spring"]
        ["adjasjh"]
        ["adjasjh"]
        ["java"] 
]

ExpectedList:

[java,C,node,reactjs,spring,..]

标签： javascriptarraysnode.jslist

解决方案

加入数组，改成小写，用逗号分割，转换成Set得到唯一词，然后传回数组：

const arr = [["java,NO,C,Node,ReactJs"],["c","Spring"],["undefined"],["asdja"],["Java","Spring"],["adjasjh", "Spring-roll"],["adjasjh"],["java", "javascript", "java-script"]];

const result = [...new Set(arr.join().toLowerCase().split(','))];

console.log(result);

较旧的答案 - 并非在所有情况下都有效：

您可以加入数组数组，并使用String.match()负前瞻 RegExp来获取唯一字符串：

const arr = [["java,NO,C,Node,ReactJs"],["c","Spring"],["undefined"],["asdja"],["Java","Spring"],["adjasjh", "Spring-roll"],["adjasjh"],["java", "javascript", "java-script"]];

const result = arr.join()
  .match(/([^,]+\b)(?!.+\1[,|$])/ig);

console.log(result);

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