首页 > 解决方案 > 需要使用用户在 codeigniter 中添加的 datatable_json 显示获取数据

问题描述

我正在从事 UNILEVEL MLM 项目,需要获取用户添加的用户数据。如果我把 $wh[] = "mobile_no =referred_by_id"; 随机显示 1 个结果,但我需要通过会话进行验证。在此,我在会话中使用 Mobile_no 并以添加成员的形式在 refer_by_id 中获取移动编号条目。我需要显示会话是否移动。在referred_by_id 中匹配显示所有数据,其中仅随机显示1 个。请帮我

模型

public function get_all_users(){
        $wh =array();
        $SQL ='SELECT * FROM ci_users';
        $wh[] = "$this->session->userdata('mobile_no') = referred_by_id";
        if(count($wh)>0)
        {
            $WHERE = implode(' and ',$wh);
            return $this->datatable->LoadJson($SQL,$WHERE);
        }
        else
        {
            return $this->datatable->LoadJson($SQL);
        }
    }

控制器

public function datatable_json(){                                      
        $records = $this->user_working->get_all_users();
        $data = array();
        foreach ($records['data']  as $row) 
        {  
            $status = ($row['is_active'] == 0)? 'inactive': 'active'.'<span>';
            $disabled = ($row['is_admin'] == 1)? 'disabled': ''.'<span>';
                            $data[]= array(
                ucfirst($row['firstname']),
                $row['email'],
                date('F j, Y',strtotime($row['created_at'])),
                '<span class="btn bg-teal  waves-effect" title="status">'.getGroupyName($row['role']).'<span>', // get Group name by ID (getGroupyName() is a helper function)
                '<span class="btn bg-blue  waves-effect" title="status">'.$status.'<span>',         

                '<a title="Delete" class="delete btn btn-sm btn-danger pull-right '.$disabled.'" data-href="'.base_url('user/users/del/'.$row['id']).'" data-toggle="modal" data-target="#confirm-delete"> <i class="material-icons">delete</i></a>
                <a title="View" class="view btn btn-sm btn-info pull-right" href="'.base_url('user/users/edit/'.$row['id']).'"> <i class="material-icons">visibility</i></a>',

            );
        }
        $records['data']=$data;
        echo json_encode($records);                        
    }

标签: phpsqlcodeigniter

解决方案


会话无法转换为字符串,您正在将会话值传递给列以签入查询

$wh[]通过以下代码更新您的

$wh[] = "`referred_by_id` = '{$this->session->userdata('mobile_no')}'";

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