java - PHP文件中的JSON返回垃圾

问题描述

我正在尝试从我的站点 example.net/index.php 获取 JSON 文件，但是我总是在 Android 应用程序中获取某种 HTML 而不是 JSON 对象。

返回字符串：

<html><body><script type="text/javascript" src="/aes.js" ></script><script>function toNumbers(d){var e=[];d.replace(/(..)/g,function(d){e.push(parseInt(d,16))});return e}function toHex(){for(var d=[],d=1==arguments.length&&arguments[0].constructor==Array?arguments[0]:arguments,e="",f=0;f<d.length;f++)e+=(16>d[f]?"0":"")+d[f].toString(16);return e.toLowerCase()}var a=toNumbers("f655ba9d09a112d4968c63579db590b4"),b=toNumbers("98344c2eee86c3994890592585b49f80"),c=toNumbers("674bdf26f9a5fe3df1461aafc3120641");document.cookie="__test="+toHex(slowAES.decrypt(c,2,a,b))+"; expires=Thu, 31-Dec-37 23:55:55 GMT; path=/"; location.href="http://example.net/index.php?i=1";</script><noscript>This site requires Javascript to work, please enable Javascript in your browser or use a browser with Javascript support</noscript></body></html>

调用网址：

<?php
  $results = array(
      "result"   => "success",
      "username" => "some username",
      "projects" => "some other value"
  );
  header('Content-type: application/json');
  echo json_encode($results);
?>

代码：

public String getJSON(String url, int timeout) {
        HttpURLConnection c = null;
        try {
            URL u = new URL(url);
            c = (HttpURLConnection) u.openConnection();
            c.setRequestMethod("GET");
            c.setRequestProperty("Content-length", "0");
            c.setUseCaches(false);
            c.setAllowUserInteraction(false);
            c.setConnectTimeout(timeout);
            c.setReadTimeout(timeout);
            c.connect();
            int status = c.getResponseCode();

            switch (status) {
                case 200:
                case 201:
                    BufferedReader br = new BufferedReader(new InputStreamReader(c.getInputStream()));
                    StringBuilder sb = new StringBuilder();
                    String line;
                    while ((line = br.readLine()) != null) {
                        sb.append(line+"\n");
                    }
                    br.close();
                    return sb.toString();
            }

        } catch (MalformedURLException ex) {
            Logger.getLogger(getClass().getName()).log(Level.SEVERE, null, ex);
        } catch (IOException ex) {
            Logger.getLogger(getClass().getName()).log(Level.SEVERE, null, ex);
        } finally {
            if (c != null) {
                try {
                    c.disconnect();
                } catch (Exception ex) {
                    Logger.getLogger(getClass().getName()).log(Level.SEVERE, null, ex);
                }
            }
        }
        return null;
    }

如何获取 JSON 文件而不是此 HTML 代码？

标签： javaphpandroidjson

c = (HttpURLConnection) u.openConnection(); c.setRequestMethod("GET"); c.setRequestProperty("Content-length", "0"); c.setRequestProperty("Content-type", "application/json; charset=utf-8"); c.setUseCaches(false);

java - PHP文件中的JSON返回垃圾

问题描述

解决方案

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