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python - Django如何对字典列表进行分页

问题描述

我有这个函数，可以从 Stackoverflow Api 获取数据，如下所示，并将它们显示在 html 表中。有没有办法对这个字典列表进行分页，以便在每页上显示 10 个结果？

视图.py：

def get_questions(request):
    context = {}
    url = 'https://api.stackexchange.com/2.2/questions'
    params = {  'fromdate':'1525858177',
                'todate':'1525904006',
                'order':'desc',
                'sort':'activity',
                'tagged':'python',
                'site':'stackoverflow'
            }
    r = requests.get(url, params=params).json()
    dataList = []
    for item in r['items']:
        dataList.append({
            'owner': item['owner']['display_name'],
            'title': item['title'],
            'creation_date': datetime.datetime.fromtimestamp(float(item['creation_date'])),
            'is_answered': item['is_answered'], # (yes / no)
            'view_count': item['view_count'],
            'score':item['score'],
            'link':item['link'],
            'answer_count':item['answer_count']
        })

    template = 'questions/questions_list.html'
    context['data'] = dataList
    return render(request,template,context)

问题列表.html：

  <table id="myTable" class="table table-hover">
    <thead>
      <tr>
        <th scope="col">Owner</th>
        <th scope="col">Title</th>
        <th scope="col">Creation date</th>
        <th scope="col">Is answered</th>
        <th scope="col">View count</th>
        <th scope="col">Score</th>
      </tr>
    </thead>
    <tbody>
        {% for d in data %}
      <tr>
        <td>{{ d.owner }}</td>
        <td><a href="{{ d.link }}" target="blank">{{ d.title }}</a></td>
        <td>{{ d.creation_date }}</td>
        <td>{{ d.is_answered|yesno:"yes,no" }}</td>
        <td>{{ d.view_count }}</td>
        <td>{{ d.score }}</td>
      </tr>
      {% endfor %}
    </tbody>
  </table>

标签： pythondjangopagination

解决方案

Django 提供了一些类来帮助您管理分页数据——也就是说，数据被拆分为多个页面，带有“上一个/下一个”链接。这些类位于 django/core/paginator.py 中。

给 Paginator 一个对象列表，加上您希望在每个页面上拥有的项目数，它为您提供了访问每个页面的项目的方法：

>>> from django.core.paginator import Paginator
>>> objects = ['john', 'paul', 'george', 'ringo']
>>> p = Paginator(objects, 2)

>>> p.count
4
>>> p.num_pages
2
>>> type(p.page_range)
<class 'range_iterator'>
>>> p.page_range
range(1, 3)

>>> page1 = p.page(1)
>>> page1
<Page 1 of 2>
>>> page1.object_list
['john', 'paul']

>>> page2 = p.page(2)
>>> page2.object_list
['george', 'ringo']
>>> page2.has_next()
False
>>> page2.has_previous()
True
>>> page2.has_other_pages()
True
>>> page2.next_page_number()
Traceback (most recent call last):
...
EmptyPage: That page contains no results
>>> page2.previous_page_number()
1
>>> page2.start_index() # The 1-based index of the first item on this page
3
>>> page2.end_index() # The 1-based index of the last item on this page
4

>>> p.page(0)
Traceback (most recent call last):
...
EmptyPage: That page number is less than 1
>>> p.page(3)
Traceback (most recent call last):
...
EmptyPage: That page contains no results

我希望这些示例代码片段有助于解决您的查询！

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