arrays - 弹性搜索使用 javascript 将 json 对象数组展平为单级

Question

我面临将我的弹性查询响应（只有我想要 _source 详细信息）扁平化为单级数组的问题。

请在下面找到弹性响应：

使用（ response.hits.hits ）我能够访问数据数组，但无法将对象数组展平为单层

当前数组：

var current_array = [
    {
        "_id": "gSdhs8aPjcUjiIs6ey85",
        "_score": 1,
        "_source": {
            "business_type": "Primary Only",
            "ceo_name": "Tim Cook",
            "city": "San Ramon",
            "company_id": "gSdhs8aPjcUjiIs6ey85",
            "company_name": "Apple Inc."
        }
    },
    {
        "_id": "v2bdB5F3PbLzziayKikS",
        "_score": 1,
        "_source": {
            "bankruptcy_activity": "No",
            "business_type": "Primary Only",
            "ceo_name": "Andrew N. Liveris",
            "city": "New York",
            "company_id": "v2bdB5F3PbLzziayKikS",
            "company_name": "General Electric",
            "country": "United States"
        }
    }
];

期望的结果：

var desired_array = [{
        "_id": "gSdhs8aPjcUjiIs6ey85",
        "_score": 1,
        "_source_business_type": "Primary Only",
        "_source_ceo_name": "Tim Cook",
        "_source_city": "San Ramon",
        "_source_company_id": "gSdhs8aPjcUjiIs6ey85",
        "_source_company_name": "Apple Inc."
    },
    {
        "_id": "v2bdB5F3PbLzziayKikS",
        "_score": 1,
        "_source_business_type": "Primary Only",
        "_source_ceo_name": "Andrew N. Liveris",
        "_source_city": "New York",
        "_source_company_id": "v2bdB5F3PbLzziayKikS",
        "_source_company_name": "General Electric",
        "_source_country": "United States"
    }
];

我尝试了下面的代码，但它正在转换为我不想要的单个数组：

var flattenObject = function (ob) {
    var toReturn = [];
    var flatObject;
    for (var i in ob) {
        if (!ob.hasOwnProperty(i)) {
            continue;
        }
        if ((typeof ob[i]) === 'object') {
            flatObject = flattenObject(ob[i]);
            for (var x in flatObject) {
                if (!flatObject.hasOwnProperty(x)) {
                    continue;
                }
                toReturn[i + (!!isNaN(x) ? '.' + x : '')] = flatObject[x];
            }
        } else {
            toReturn[i] = ob[i];
        }
    }
    return toReturn;
};

它给出的输出如下：

var undesired_array = [
    0. _index: "company",
    0. _score: 1,
    0. _source.ceo_name: "Tim Cook",
    0. _source.city: "San Ramon",
    0. _source.company_name: "Apple Inc.",
    1. _id: "v2bdB5F3PbLzziayKikS",
    1. _index: "company",
    1. _score: 1,
    1. _source.ceo_name: "Andrew N. Liveris",
    1. _source.city: "New York",
    1. _source.company_id: "v2bdB5F3PbLzziayKikS",
    1. _source.company_name: "General Electric"
];

标签： arraysjsonobjectflatten

Answer 1

考虑到每个对象中只有一层嵌套，这段代码应该可以工作。

function flattenObject(input) {
    return input.map(function (doc) {
        let flatDoc = {};
        Object.keys(doc).forEach(function (key) {
            if (doc[key]instanceof Object) {
                Object.keys(doc[key]).forEach(function (innerkey) {
                    flatDoc[key + "_" + innerkey] = doc[key][innerkey];
                });
            } else {
                flatDoc[key] = doc[key];
            }
        });
        return flatDoc;
    });
}