python - Python - 如何转换为 int 字符串矩阵？

Question

我得到了列表的二维矩阵，其中包含如下字符串：

somelist = [["12","10","0"]
            ["0","33","60"]]

我需要将所有这些转换str为int. 到目前为止，我的代码是：

for i in somelist:
        for j in i:
            j = int(j)

标签： pythonpython-3.x

Answer 1

或使用地图：

>>> [list(map(int, x)) for x in somelist]
[[12, 10, 0], [0, 33, 60]]

这是您的固定代码：

somelist = [["12","10","0"],
            ["0","33","60"]]

for n, i in enumerate(somelist):
    for k, j in enumerate(i):
        somelist[n][k] = int(j)

print(somelist)

输出：

[[12, 10, 0], [0, 33, 60]]