时间戳

首页 > 解决方案 > 根据条件连接行中的值

r - 根据条件连接行中的值

问题描述

我有一个数据框df（参见下面的代码），其中包含近 100,000 行显示我的程序联系人列表。该列表有一列显示与联系人关联的计划program和组织，一列表示联系人在计划中的角色。O_ID每当联系人在多个程序中或在程序中具有多个角色时，都会为该联系人创建另一行，并且联系人角色字段值会发生变化。

First   Last    C_ID    OrgName O_ID Program    Role
John    Smith   10045   Acme    901 Buildings   Primary
John    Smith   10045   Acme    901 Buildings   Communications
John    Smith   10045   Acme    901 Homes       Primary
Teddy   Bush    10046   Acme    901 Buildings   Primary
Teddy   Bush    10046   Acme    901 Buildings   Signatory
Jess    Clinton 10050   Consult 904 Homes       Signatory
Jess    Clinton 10050   Consult 904 Homes       Primary
Jess    Clinton 10050   Consult 904 Homes       Communications

出于演示目的，我试图尽量减少行数。具体来说，如果一个联系人在同一个组织和同一个程序中，我只希望联系人出现在一行上（而不是目前的几个），并将联系人角色组合成一个字符串。

我尝试了这段代码，它部分有效：ddply(df,.(df$C_ID, df$Program, df$O_ID), paste, sep=",")

结果如下：

df$C_ID df$Program df$O_ID                        V1                                 V2
1       10045      Buildings         901         c("John", "John")                c("Smith", "Smith")
2       10045          Homes         901                      John                              Smith
3       10046      Buildings         901       c("Teddy", "Teddy")                  c("Bush", "Bush")
4       10050          Homes         904 c("Jess", "Jess", "Jess") c("Clinton", "Clinton", "Clinton")
                      V3                                 V4               V5                           V6
1        c(10045, 10045)                  c("Acme", "Acme")      c(901, 901)  c("Buildings", "Buildings")
2                  10045                               Acme              901                        Homes
3        c(10046, 10046)                  c("Acme", "Acme")      c(901, 901)  c("Buildings", "Buildings")
4 c(10050, 10050, 10050) c("Consult", "Consult", "Consult") c(904, 904, 904) c("Homes", "Homes", "Homes")
                                           V7
1              c("Primary", "Communications")
2                                     Primary
3                   c("Primary", "Signatory")
4 c("Signatory", "Primary", "Communications")

问题是

1）列被重新排列（注意我的实际数据集中还有更多列）并且列名消失了

2) 唯一改变值的列应该在Role列中。但是，即使合并的值相同，结果也会合并大多数列的值。例如，在结果列V1（名字列）中，返回c("John", "John"). 它应该只是读“约翰”。唯一应该具有不同值的列是 columnV7 c("Primary", "Communications")

df<-structure(list(First = c("John", "John", "John", "Teddy", "Teddy", 
"Jess", "Jess", "Jess"), Last = c("Smith", "Smith", "Smith", 
"Bush", "Bush", "Clinton", "Clinton", "Clinton"), C_ID = c(10045L, 
10045L, 10045L, 10046L, 10046L, 10050L, 10050L, 10050L), OrgName = c("Acme", 
"Acme", "Acme", "Acme", "Acme", "Consult", "Consult", "Consult"
), O_ID = c(901L, 901L, 901L, 901L, 901L, 904L, 904L, 904L), 
    Program = c("Buildings", "Buildings", "Homes", "Buildings", 
    "Buildings", "Homes", "Homes", "Homes"), Role = c("Primary", 
    "Communications", "Primary", "Primary", "Signatory", "Signatory", 
    "Primary", "Communications")), .Names = c("First", "Last", 
"C_ID", "OrgName", "O_ID", "Program", "Role"), class = "data.frame", row.names = c(NA, 
-8L))

标签： rmergedplyrpaste

解决方案

你需要的paste是collapse = ", "，不是sep。使用 acollapse从所有输入中创建一个字符串。我通过对所有识别列（名称、组织、程序等）进行分组，然后将角色折叠到summarise.

library(tidyverse)

df %>%
  group_by(First, Last, C_ID, OrgName, O_ID, Program) %>%
  summarise(roles_mult = paste(Role, collapse = ", "))
#> # A tibble: 4 x 7
#> # Groups:   First, Last, C_ID, OrgName, O_ID [?]
#>   First Last     C_ID OrgName  O_ID Program   roles_mult                  
#>   <chr> <chr>   <int> <chr>   <int> <chr>     <chr>                       
#> 1 Jess  Clinton 10050 Consult   904 Homes     Signatory, Primary, Communi…
#> 2 John  Smith   10045 Acme      901 Buildings Primary, Communications     
#> 3 John  Smith   10045 Acme      901 Homes     Primary                     
#> 4 Teddy Bush    10046 Acme      901 Buildings Primary, Signatory

推荐阅读