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ios - 按位置打印数组显示为空

问题描述

目标是这样的：

这是我提取数据的方式：

import Foundation
import SwiftyJSON

class restaurant {

    //Json
     var id: Int!
     var name: String!
     var address: String!
     var city: String!
     var logo: String!
     var state: String!
     var postKey: String!


    //Second
    var ids: Int!
    var names: String!
    var aAddress: String!
    var citys: String!
    var logos: String!
    var states: String!

    var distance : Double = 0

    //Importing data from server. Bring moto. Make sure you are able to get details in postman prior to adding any other variables
    init(json: JSON) {
        self.id = json["id"].int
        self.name = json["dispensary_name"].string
        self.address = json["street_address"].string
        self.logo = json["logo"].string
        self.city = json["city"].string
        self.state = json["state"].string
    }

    init(postKey: String, postData: Dictionary<String, AnyObject>) {
        self.postKey = postKey

//        self.ids = postData[self.id]?.int
        self.names = postData[self.name]?.string
        self.aAddress = postData[self.address]?.string
        self.citys = postData[self.city]?.string
        self.logos = postData[self.logo]?.string
        self.states = postData[self.state]?.string
    }
}

这是我的数组：//加载餐厅列表。

func loadRestaurants() {
    Helpers.showActivityIndicator(activityIndicator, view)

    APIManager.shared.getRestaurants { (json) in
        if json != nil {
            self.restaurants = []
                //Adds all items into the array list dist then goes through them all.
            if let listDis = json["restaurant"].array {
                for item in listDis {

                    let address = item["street_address"].string! + ", " + item["city"].string! + ", " + item["state"].string!

                    self.getLocation(address, { (dis) in
                                        self.disLocation = dis
                    })

                    //snap = item, snapshot = listdict

                    if let snapValue = item.array as? [String:AnyObject],
                       let venueLat = self.disLocation?.coordinate.latitude,
                       let venueLong = self.disLocation?.coordinate.longitude {
                        print("snapValue ,", snapValue)
                        let distance = self.calculateDistance(userlat: self.userLatt, userLon: self.userLonn, venueLat: venueLat, venueLon: venueLong)

                        if distance <= 15 {
                            let key = item.string
                            let restaurant = Restaurant(postKey: key!, postData: snapValue)
                            restaurant.distance = distance
                            self.restaurants.append(restaurant)
                            print("restaurant :", snapValue)
                        }
                    }
                }

                if self.restaurants.count == 0 {
                    let alert = UIAlertController(title: "Oh No!!!", message: "We Only Deliver To New Jersey", preferredStyle: UIAlertControllerStyle.alert)
                    alert.addAction(UIAlertAction(title: "OK", style: .default, handler: { action in
                         }))
                    self.present(alert, animated: true, completion: nil)
                }
                self.restaurants.sort {                                
                    $0.distance < $1.distance
                }
            }
            self.restaurants.reloadData()
            Helpers.hideActivityIndicator(self.activityIndicator)
        }
    }
}

我不确定我应该在这里做什么。任何意见将是有益的。

项目输出：

"state" : "New Jersey",
  "city" : "Highland Park",
  "id" : 3,
  "dispensary_name" : "Down South Taste",
  "street_address" : "4422 knotwood ct",
  "zip_Code" : 56430,
  "phone" : "444-334-0888",

标签： iosarraysjsonswiftcllocation

解决方案

您用于 Restaurant 对象（第二个）的 init 方法显然是错误的，并且会导致运行时崩溃，因为您正在解包 nil 值。

self.names = postData[self.name]?.string

name这里是 nil 但声明为

var name: String!

在使用属性作为键而不是字符串常量来阅读字典时，我真的不明白你想要实现什么？

也许做类似的事情

let nameKey = "dispensary_name"
...

self.names = postData[nameKey]?.string

如果我理解正确，您的程序不会崩溃，这告诉我们构造函数永远不会被调用。我的猜测是，它是周围 if 语句中的条件失败，并且条件的第一部分在您调用.arrayjson 项并将结果类型转换为字典的地方看起来是错误的

if let snapValue = item.array as? [String:AnyObject], ...

.array.这里看起来不对，虽然我不知道您的 json 格式，但您之前将该item属性作为字典访问，这不是item您的字典吗？

希望这将帮助您继续前进。

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