首页 > 解决方案 > Laravel 将自定义中间件添加到路由组

问题描述

在我的 Web 应用程序中,我有管理面板,我正在尝试通过以下代码访问他们具有管理员角色的用户:

namespace App\Http\Middleware;
use Closure;
class CheckUserAdminRole
{
    public function handle($request, Closure $next)
    {
        if (auth()->check()) {
            if (auth()->check() && !auth()->user()->hasRole('admin')) {
                auth()->logout();
                return redirect(route('system.messages','userIsNotAdmin'));
            }
        }
        return $next($request);
    }
}

在我的路线中,我有这个路线组:

Route::group(['namespace' => 'Dashboard', 'middleware' => ['auth:web'], 'prefix' => 'dashboard'], function () {
    $this->group(['prefix' => 'administrator'], function () {
        $this->get('panel', 'AdminController@index');
});

我的内核:

protected $middleware = [
    \Illuminate\Foundation\Http\Middleware\CheckForMaintenanceMode::class,
    \Illuminate\Foundation\Http\Middleware\ValidatePostSize::class,
    ...
    \App\Http\Middleware\CheckUserAdminRole::class,
];

现在,当我CheckUserAdminRole使用以下代码将中间件添加到路由组时:

Route::group(['namespace' => 'Dashboard', 'middleware' => ['auth:web','CheckUserAdminRole'], 'prefix' => 'dashboard'], function () {

我收到此错误:

Class CheckUserAdminRole does not exist

此代码无法解决我的问题:

php artisan route:clear
php artisan cache:clear
php artisan config:clear
composer dump-autoload

标签: laravellaravel-5.6

解决方案


而不是在数组中注册你的中间件$middleware,你应该$routeMiddleware像这样注册它:

protected $routeMiddleware = [
    ...
    'checkAdmin' => \App\Http\Middleware\CheckUserAdminRole::class,
];

注意:在数组中注册中间件会$middleware导致它为每个请求执行,因此不适用于特定路由。

然后你可以在你的路线中使用它的checkAdmin名字:

Route::group(['namespace' => 'Dashboard', 'middleware' => ['auth:web','checkAdmin'], 'prefix' => 'dashboard'], function () {

来源


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