首页 > 解决方案 > 如何在 URI 行中将对象作为查询参数传递?

问题描述

你能帮我解释一下我应该如何传递作者值吗?

@GetMapping(value = "/search")
    public ResponseEntity<List<Book>> searchBooksByTitleAndAuthor(
            @RequestParam(value = "title", required = false) final String title,
            @RequestParam(value = "author", required = false) final Author author) {
        HttpStatus httpStatus = HttpStatus.OK;
        List<Book> books = null;
        if (title == null && author == null) {
            log.info("Empty request");
            httpStatus = HttpStatus.BAD_REQUEST;
        } else if (title == null || author == null) {
            books = bookService.getBooksByTitleOrAuthor(title, author);
        } else {
            Optional<Book> book = bookService.getBookByTitleAndAuthor(title, author);
            if (book.isPresent()) {
                books = Arrays.asList(book.get());
            }
        }
        if (books == null) {
            return new ResponseEntity<>(httpStatus);
        } else {
            return new ResponseEntity<>(books, httpStatus);
        }
    }

Author看起来像这样的类:

@Entity
@NoArgsConstructor
@AllArgsConstructor
@Getter
@EqualsAndHashCode
@ToString
public final class Author {

    @Id
    @GeneratedValue(strategy=GenerationType.IDENTITY)
    private Long id;

    private String name;

    private LocalDate dateOfBirth;

    private String bio;
}

在这种情况下使用 author 或 @RequestParam 而不是请求正文是一种好方法吗?我考虑过只请求作为作者姓名的字符串,但这会影响服务的方法。

标签: javaspringspring-mvcmodel-view-controller

解决方案


根据https://lankydanblog.com/2017/03/11/passing-data-transfer-objects-with-get-in-spring-boot/,......你可以(在你设置一些转换注释之后author.dateOfBirth) :

  1. 在字符串参数上使用@RequestParam(并让您的控制器/某人进行转换):

        ..., @RequestParam(value = "author", required = false) final String author) { 
    
         ...final Author author = new ObjectMapper().setDateFormat(simpleDateFormat)
                                 .readValue(author, Author.class);
    

    在这种情况下,您会要求:

    http://localhost:8080/myApp/search?title=foo&author={"id"="1",...}
    
  2. 或者:省略@RequestParam,但传递对象(让spring关心转换):

    ...(@RequestParam(value = "title", required = false) final String title,
         final Author author)
    

    并要求:

    http://localhost:8080/myApp/search?title=foo&id=1&name=Donald E. Knuth&...
    

也可以看看:


推荐阅读