首页 > 解决方案 > 自定义 Celery 任务类无法正常工作

问题描述

我正在努力让 Celery 工作。一般来说,我是 Python 的新手,显然是 Celery 的新手,我正在尝试获得基本的示例工作。我想运行一个后台任务,只要它还活着,它就应该保持它的状态。因此,我尝试实现从客户端脚本调用时递增整数变量的基本示例。我正在使用 raspbian 图像处理 Raspberry Pi。这是我的工人任务代码:

from celery import Task, registry, Celery
import celery

celery = Celery('tasks', broker='redis://localhost:6379',backend='redis://localhost:6379')

class MyTask(celery.Task):
        a = 0
        def __init__(self):
                self.a = 0

        def increment(self, x):
                self.a += x
                return self.a
        @property
        def a(self):
                return a

@celery.task(Base=MyTask)
def mytask(x):
        mytask.increment(x)
        return mytask.a

这是调用脚本:

from tasks import mytask

result = mytask.delay(2)
print result.get(timeout=1)

这会产生以下错误:

[2018-05-21 15:08:23,889: DEBUG/MainProcess] TaskPool: Apply <function _fast_trace_task at 0x7610cdf0> (args:('tasks.mytask', '3ae83225-faee-4dc0-a6c1-1a7e7e5eaca2', {'origin': 'gen27381@raspberrypi', 'lang': 'py', 'task': 'tasks.mytask', 'group': None, 'root_id': '3ae83225-faee-4dc0-a6c1-1a7e7e5eaca2', u'delivery_info': {u'priority': 0, u'redelivered': None, u'routing_key': 'celery', u'exchange': u''}, 'expires': None, u'correlation_id': '3ae83225-faee-4dc0-a6c1-1a7e7e5eaca2', 'retries': 0, 'timelimit': [None, None], 'argsrepr': '(2,)', 'eta': None, 'parent_id': None, u'reply_to': 'fdebe38f-7353-3ef2-920b-74f76a294ff7', 'id': '3ae83225-faee-4dc0-a6c1-1a7e7e5eaca2', 'kwargsrepr': '{}'}, '[[2], {}, {"chord": null, "callbacks": null, "errbacks": null, "chain": null}]', 'application/json', 'utf-8') kwargs:{})
[2018-05-21 15:08:23,894: DEBUG/MainProcess] Task accepted: tasks2.mytask[3ae83225-faee-4dc0-a6c1-1a7e7e5eaca2] pid:27366
Traceback (most recent call last):
  File "test2.py", line 4, in <module>
    print result.get(timeout=1)
  File "/usr/local/lib/python2.7/dist-packages/celery/result.py", line 194, in get
    on_message=on_message,
  File "/usr/local/lib/python2.7/dist-packages/celery/backends/async.py", line 191, in wait_for_pending
    return result.maybe_throw(callback=callback, propagate=propagate)
  File "/usr/local/lib/python2.7/dist-packages/celery/result.py", line 299, in maybe_throw
    self.throw(value, self._to_remote_traceback(tb))
  File "/usr/local/lib/python2.7/dist-packages/celery/result.py", line 292, in throw
    self.on_ready.throw(*args, **kwargs)
  File "/usr/local/lib/python2.7/dist-packages/vine/promises.py", line 217, in throw
    reraise(type(exc), exc, tb)
  File "<string>", line 1, in reraise
celery.backends.base.AttributeError: 'mytask' object has no attribute 'increment'
[2018-05-21 15:08:23,910: ERROR/ForkPoolWorker-2] Task tasks.mytask[3ae83225-faee-4dc0-a6c1-1a7e7e5eaca2] raised unexpected: AttributeError("'mytask' object has no attribute 'increment'",)
Traceback (most recent call last):
  File "/usr/local/lib/python2.7/dist-packages/celery/app/trace.py", line 374, in trace_task
    R = retval = fun(*args, **kwargs)
  File "/usr/local/lib/python2.7/dist-packages/celery/app/trace.py", line 629, in __protected_call__
    return self.run(*args, **kwargs)
  File "/home/pi/example/tasks.py", line 20, in mytask
    mytask.increment(x)
  File "/usr/local/lib/python2.7/dist-packages/celery/local.py", line 146, in __getattr__
    return getattr(self._get_current_object(), name)
AttributeError: 'mytask' object has no attribute 'increment'

使用命令添加工人:

celery -A 任务工作者 --loglevel=debug

和简单的测试脚本

蟒蛇测试.py

我还尝试直接访问“a”变量,结果出现了同样的错误。很明显,我做错了一些非常基本的事情,但我不知道是什么。

标签: pythonredisraspberry-picelerydaemon

解决方案


好的,所以问题确实非常基本。定义自定义任务类的语法不是 ChildClass(Base=ParentClass) 而是 ChildClass(base=ParentClass)... 我一定是从某个示例中复制了它,而解释器从未想过要抱怨其中的任何一个。问题中的示例还有其他几个问题这里是实际执行应执行操作的代码:

    from celery import Task, registry, Celery
    import celery


    class MyTask(celery.Task):
            a = 0

            def increment(self, x):
                    self.a += x
                    return self.a

    celery = Celery('tasks', broker='redis://localhost:6379',backend='redis://localhost:6379')
    @celery.task(base=MyTask)
    def fookyou(x):
            val = fookyou.increment(x)
            return val

请注意,我还修改了任务名称,以防它与自定义类名称混合,而唯一的区别是大写字母。要求口译员发现这种类型的错误显然太多了......


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