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linux - GREP 或 Regex 搜索具有特定系列的唯一字符

问题描述

我是新手，我想使用具有唯一 ID 列表的 grep 或正则表达式搜索一个巨大的文件。

示例文件：

/icon_edit.png\" \/><\/a> AP-28992 : ABCD-1103_01 [v1]","2","2012-10-27 18:40:47","2012-01-04 13:22:41"],
["shawn","extra\/fax","<!-- 0000000000 --><a href=\"javascript:openTCEditWindow(0000,000);\"><img title=\"
TSD\" src=\"gui\/themes\/default\/images\/icon_edit.png\" \/><\/a> AP-28993 : ABCD-1103_02
[v1]","2","2012-10-27 18:40:47","2012-01-04 13:22:41"],
["shawn","extra\/traax","<!-- 0000000000 --> ABCD_110_01

应在下面唯一过滤，例如：

ABCD-1103
ABCD-110

标签： linuxunix

解决方案

我猜ABCD-110是你的输入模式和空格是分隔符

所以如果你的输入文件即。abc.txt 就像（我修改了最后一行）

$cat abc.txt 
/icon_edit.png\" \/><\/a> AP-28992 : ABCD-1103_01 [v1]","2","2012-10-27
18:40:47","2012-01-04 13:22:41"],
["shawn","extra\/fax","<!-- 0000000000 --><a
href=\"javascript:openTCEditWindow(0000,000);\"><img title=\"
TSD\" src=\"gui\/themes\/default\/images\/icon_edit.png\" \/><\/a> AP-28993 :
ABCD-1103_02
[v1]","2","2012-10-27 18:40:47","2012-01-04 13:22:41"],
["shawn","extra\/traax","<!-- 0000000000 --> ABCD-110_01

然后以下工作：

$cat abc.txt  | grep -ow "ABCD-110.*" | awk '{print $1}'
ABCD-1103_01
ABCD-1103_02
ABCD-110_01

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