ios - 在 Swift 中将多个参数传递给 UIAlertAction

Question

我一直在尝试找到一种将多个参数传递给 UIAlertAction 的方法。以下是我的代码。我想将“源”字符串传递给警报的 joinSelected 操作。

我收到这样的错误：

无法将类型“（）”的值转换为预期的参数类型“（（UIAlertAction）->

fileprivate func showBetaAlert(source: String)  {
        let betaAlert =  UIAlertController.betaProgramAlert()
        let joinAction = UIAlertAction(title: "Join", style: UIAlertActionStyle.default, handler: joinSelected(alert: <#UIAlertAction#>, source: source))
        let cancelAction = UIAlertAction(title: "Cancel", style: UIAlertActionStyle.cancel, handler: cancelSelected)

        betaAlert.addAction(cancelAction)
        betaAlert.addAction(joinAction)

        present(betaAlert, animated: true, completion: nil)

    }

fileprivate func joinSelected(alert: UIAlertAction, source: String) {
        let betaAlert = UIAlertController.signUpAlert()
        let cancelAction = UIAlertAction(title: "Cancel", style: .cancel, handler: dismissEmailAction)
        let submitAction = UIAlertAction(title: "Submit", style: .default , handler: { [weak self] _ in
            guard let stelf = self else { return }
            let email = betaAlert.textFields![0] as UITextField
            stelf.submitAction(email: email.text!)
        })

        betaAlert.addAction(cancelAction)
        betaAlert.addAction(submitAction)

        present(betaAlert, animated: true, completion: nil)
    }

标签： iosswiftuialertaction

Answer 1

替换这一行：

let joinAction = UIAlertAction(title: "Join", style: UIAlertActionStyle.default, handler: joinSelected(alert: <#UIAlertAction#>, source: source))

和：

let joinAction = UIAlertAction(title: "Join", style: UIAlertActionStyle.default, handler: { [weak self] _ in
    joinSelected(source: source)
})

并更新joinSelected为：

fileprivate func joinSelected(source: String) {