mysql - sql 语法错误以防万一
问题描述
我有一个格式如下的表格。
EMP NUMBER, ATT DATE, ATT TIME
00001 01-03-2018 08:45
00001 01-03-2018 20:50
00001 02-03-2018 08:00
00001 02-03-2018 18:50
我被要求得到以下结果:
EMP NUMBER, ATT DATE, IN TIME, OUT TIME
00001 01-03-2018 08:45 20:50
00001 02-03-2018 08:00 18:50
我设法使用以下查询获得:
SELECT EMP_NUMBER, ATT_DATE,MIN(ATT_TIME) AS IN_TIME,MAX(ATT_TIME) AS OUT_TIME
INTO TABLE1
FROM FJ
GROUP BY EMP_NUMBER,ATT_DATE
即使我得到了我想要的答案,但我担心员工在晚上 10 点登录并在第二天早上 5 点离开时的情况,因此我尝试了以下操作:
SELECT EMP_NUMBER, ATT_DATE,
CASE
WHEN ATT_TIME >= 12
THEN MIN(ATT_TIME)
ELSE MAX(ATT_TIME)
AS IN_TIME,
CASE
WHEN ATT_TIME < 12
THEN MIN(ATT_TIME)
ELSE MAX(ATT_TIME)
AS OUT_TIME,
INTO TABLE1
FROM FJ
GROUP BY EMP_NUMBER,ATT_DATE
这会在“AS”附近引发语法错误,你能帮我弄清楚我哪里出错了吗?提前致谢。
解决方案
不确定查询逻辑,但您的两个 CASE 语句都缺少“END”子句。
SELECT EMP_NUMBER, ATT_DATE,
CASE
WHEN ATT_TIME >= 12
THEN MIN(ATT_TIME)
ELSE MAX(ATT_TIME)
END --<-- You are missing "END" here
AS IN_TIME,
CASE
WHEN ATT_TIME < 12
THEN MIN(ATT_TIME)
ELSE MAX(ATT_TIME)
END --<-- and here
AS OUT_TIME --<-- also you had an extra comma here
INTO TABLE1
FROM FJ
GROUP BY EMP_NUMBER,ATT_DATE