python - Subprocess, Launch script in alternate version of Python

Question

My main script, main.py runs in python3. within it, I want to launch another script in some specified version of python.

import subprocess
pysh="/data/data/org.qpython.qpy/files/bin/qpython-android5.sh"
subprocess.call([pysh,'filetext.py'])

Question:

How can I use subprocess to open filetext.py in python2.x or 3.x interchangeably?

I have tried:

I have tried inputting several different arguments to no avail, such as:

os.system('python -2 -m filetext.txt')

or

subprocess.call(['py -2 filetext.txt'])

or

subprocess.call(['C:/Python27/python.exe filetext.txt'])

Any help would be immensely appreciated.

标签： pythonsubprocesslaunchversions

Answer 1

尝试这个 ：

subprocess.call(['C:/Python27/python.exe', "filetext.txt"])

首先给出所需可执行文件的路径，然后给出不同参数中的参数。