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python - 在 Python 中抓取一个 url

问题描述

我正在尝试从搜索页面获取阿迪达斯鞋的链接，但无法弄清楚我做错了什么。

我试过 tags = soup.find("section", {"class": "productList"}).findAll("a") 不起作用:(

我还尝试打印所有href内容，但所需的链接不在那里:(

所以我期待打印这个：

https://www.tennisexpress.com/adidas-mens-adizero-ubersonic-50-yrs-ltd-tennis-shoes-off-white-and-signal-blue-62138


from bs4 import BeautifulSoup
import requests

url = "https://www.tennisexpress.com/search.cfm?searchKeyword=BB6892"

# Getting the webpage, creating a Response object.
response = requests.get(url)

# Extracting the source code of the page.
data = response.text

# Passing the source code to BeautifulSoup to create a BeautifulSoup object for it.
soup = BeautifulSoup(data, 'lxml')

# Extracting all the <a> tags into a list.
tags = soup.find("section", {"class": "productList"}).findAll("a")

# Extracting URLs from the attribute href in the <a> tags.
for tag in tags:
    print(tag.get('href'))

这是该链接的 html 代码 

<section class="productList"> <article class="productListing"> <a class="product" href="//www.tennisexpress.com/adidas-mens-adizero-ubersonic-50-yrs-ltd-tennis-shoes-off-white-and-signal-blue-62138" title="Men`s Adizero Ubersonic 50 Yrs LTD Tennis Shoes Off White and Signal Blue" onmousedown="return nxt_repo.product_x('38698770','1');"> <span class="sale">SALE</span> <span class="image"> <img src="//www.tennisexpress.com/prodimages/78091-DEFAULT-m.jpg" alt="Men`s Adizero Ubersonic 50 Yrs LTD Tennis Shoes Off White and Signal Blue"> </span> <span class="brand"> Adidas </span> <span class="name"> Men`s Adizero Ubersonic 50 Yrs LTD Tennis Shoes Off White and Signal Blue </span> <span class="pricing"> <strong class="listPrice">$140.00</strong> <strong class="percentOff">0% OFF</strong> <strong class="salePrice">$139.95</strong> </span> <br> </a> </article> </section>

标签： pythonajaxweb-scrapingbeautifulsouppython-requests

解决方案

通过检查 Chrome DevTools 中的 Network 选项卡，您可以注意到您搜索的产品是在向https://tennisexpress-com.ecomm-nav.com/search.js. 您可以在此处查看示例响应。正如你所看到的，这是一团糟，所以我不会采用这种方法。

在您的代码中，您看不到产品，因为请求是在初始页面加载后由 JavaScript（在您的浏览器中运行）发出的。既不能独立urllib也requests不能呈现该内容。但是，您可以通过 JavaScript 支持来做到这Requests-HTML一点（它在幕后使用 Chromium）。

代码：

from itertools import chain
from requests_html import HTMLSession

session = HTMLSession()
url = 'https://www.tennisexpress.com/search.cfm?searchKeyword=adidas+boost'
r = session.get(url)
r.html.render()

links = list(chain(*[prod.absolute_links for prod in r.html.find('.product')]))

我曾经chain将所有具有绝对链接的集合连接在一起，并从中创建了一个列表。

>>> links
['https://www.tennisexpress.com/adidas-mens-barricade-2018-boost-tennis-shoes-black-and-night-metallic-62110',
 'https://www.tennisexpress.com/adidas-mens-barricade-2018-boost-tennis-shoes-white-and-matte-silver-62109',
 ...
 'https://www.tennisexpress.com/adidas-mens-supernova-glide-7-running-shoes-black-and-white-41636',
 'https://www.tennisexpress.com/adidas-womens-adizero-boston-6-running-shoes-solar-yellow-and-midnight-gray-45268']

不要忘记使用pip install requests-html.

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