时间戳

首页 > 解决方案 > 在保持单词列顺序的同时拆分单词字符串数组

ruby - 在保持单词列顺序的同时拆分单词字符串数组

问题描述

我有一个字符串

        WP(PIL)/7/2013        PUBLIC AND PANCHAYAT               MS PEMA BHUTIA            MR. S.K. CHETTRI,\n                                KABI LUNGCHUK                      MS PANILA THEENGH         ASST. GOVT.\n                                CONSTITUENCY, NORTH                MS MON MAYA SUBBA         ADVOCATE\n                                SIKKIM                             MS TASHI DOMA SHERPA      MR. KARMA THINLAY,\n                                Vs                                 MR SANGAY GURMEY          CENTRAL GOVT.\n                                THE SECRETARY, MINISTRY            BHUTIA                    COUNSEL\n                                OF SURFACE TRANSPORT               MR. JORGAY NAMKA          MR THINLAY DORJEE\n                                AND ORS.                           MR. ZANGPO SHERPA,        BHUTIA\n                                                                   AMICUS CURIAE             MS POLLIN RAI, ASST.\n                                                                                             GOVT. ADVOCATE\n

我使用 '\n' 字符拆分。结果是

["        WP(PIL)/7/2013        PUBLIC AND PANCHAYAT               MS PEMA BHUTIA            MR. S.K. CHETTRI,",
"                                KABI LUNGCHUK                      MS PANILA THEENGH         ASST. GOVT.",
"                                CONSTITUENCY, NORTH                MS MON MAYA SUBBA         ADVOCATE",
"                                SIKKIM                             MS TASHI DOMA SHERPA      MR. KARMA THINLAY,",
"                                Vs                                 MR SANGAY GURMEY          CENTRAL GOVT.",
"                                THE SECRETARY, MINISTRY            BHUTIA                    COUNSEL",
"                                OF SURFACE TRANSPORT               MR. JORGAY NAMKA          MR THINLAY DORJEE",
"                                AND ORS.                           MR. ZANGPO SHERPA,        BHUTIA",
"                                                                   AMICUS CURIAE             MS POLLIN RAI, ASST.",
"                                                                                             GOVT. ADVOCATE"]

我想为每行提取 4 列（即将字符串数组转换为矩阵）。此外，提取的字符串应该属于关联的列。例如'政府。最后一个字符串中的 ADVOCATE' 应该属于提取为 ['', '', '', 'GOVT. 提倡']

我正在使用docsplit库来解析具有表格数据的 pdf。问题是 pdf 中的每一行都有内部表，类似于下面指定的字符串数组。

我尝试获取每列单词的第一个字符的索引作为参考，并使用这些值来处理字符串，但无法找到有效的解决方案。

标签： rubyregexstring

解决方案

这是我根据上面的评论的解决方案：

require 'pp'

test_array = ["        WP(PIL)/7/2013        PUBLIC AND PANCHAYAT               MS PEMA BHUTIA            MR. S.K. CHETTRI,",
"                                KABI LUNGCHUK                      MS PANILA THEENGH         ASST. GOVT.",
"                                CONSTITUENCY, NORTH                MS MON MAYA SUBBA         ADVOCATE",
"                                SIKKIM                             MS TASHI DOMA SHERPA      MR. KARMA THINLAY,",
"                                Vs                                 MR SANGAY GURMEY          CENTRAL GOVT.",
"                                THE SECRETARY, MINISTRY            BHUTIA                    COUNSEL",
"                                OF SURFACE TRANSPORT               MR. JORGAY NAMKA          MR THINLAY DORJEE",
"                                AND ORS.                           MR. ZANGPO SHERPA,        BHUTIA",
"                                                                   AMICUS CURIAE             MS POLLIN RAI, ASST.",
"                                                                                             GOVT. ADVOCATE"]

class ColumnAnalyzer

  attr_reader :columns
  attr_accessor :array

  def initialize(array)
    @array = array
    analyze
  end

  def analyze
    lefts = Array.new
    rights = Array.new
    @array.each do |line|
      pos_left =  Array.new
      deconstruct = line.dup
      col = 0
      while m = deconstruct.match(/\s\s[^\s]{1}/) do
        left = m.offset(0)[0]+1
        pos_left[col] = col == 0 ? left : left + pos_left[col-1]
        col += 1
        deconstruct = deconstruct[left+1..-1]
      end
      lefts.push pos_left
      pos_right = Array.new
      deconstruct = line.dup
      col = 0
      while m = deconstruct.match(/[^\s]{1}\s\s/) do
        right = m.offset(0)[0]
        pos_right[col] = col == 0 ? right : right + pos_right[col-1]
        col += 1
        deconstruct = deconstruct[right+1..-1]
      end
      pos_right.push line.length
      rights.push pos_right
    end
    cols_l = lefts.collect { |a| a.size }.max 
    cols_r = rights.collect { |a| a.size }.max
    cols = [cols_l,cols_r].max # no. of columns
    @columns = Array.new
    (0..cols-1).each do |col|
      @columns[col] = Hash.new
      @columns[col][:l] = lefts.map { |a| a[col] }.min
      lefts.select { |a| a.size < cols }.map! { |a| a.unshift 0 }
      rights.select { |a| a.size < cols }.map! { |a| a.unshift 0 }
    end
    (0..cols-1).each do |col|
      @columns[col][:r]  = rights.map { |a| a[col] }.max
    end
  end

  def extract
    data = Array.new
    @array.each do |line|
      line_array = Array.new
      @columns.each do |col|
        line_array.push line[col[:l]..col[:r]].strip!
      end
      data.push line_array
    end
    data
  end

end

ca = ColumnAnalyzer.new(test_array)
data = ca.extract
pp ca.columns
pp data

=> [{:l=>7, :r=>21}, {:l=>28, :r=>54}, {:l=>62, :r=>85}, {:l=>87, :r=>113}]
[["WP(PIL)/7/2013",
  "PUBLIC AND PANCHAYAT",
  "MS PEMA BHUTIA",
  "MR. S.K. CHETTRI,"],
 ["", "KABI LUNGCHUK", "MS PANILA THEENGH", "ASST. GOVT."],
 ["", "CONSTITUENCY, NORTH", "MS MON MAYA SUBBA", "ADVOCATE"],
 ["", "SIKKIM", "MS TASHI DOMA SHERP", "MR. KARMA THINLAY,"],
 ["", "Vs", "MR SANGAY GURMEY", "CENTRAL GOVT."],
 ["", "THE SECRETARY, MINISTRY", "BHUTIA", "COUNSEL"],
 ["", "OF SURFACE TRANSPORT", "MR. JORGAY NAMKA", "MR THINLAY DORJEE"],
 ["", "AND ORS.", "MR. ZANGPO SHERPA,", "BHUTIA"],
 ["", "", "AMICUS CURIAE", "MS POLLIN RAI, ASST."],
 ["", "", "", "GOVT. ADVOCATE"]]

推荐阅读