vim - How to match the white space between two strings in vim?

Question

4250682 orderNumber: 60360981400                         orderID：4250682 

There could be white spaces or tab between "60360981400" and "orderID". How to match those spaces and replace it with only one space?

orderNumber：\d\+.*orderID 

This can match the pattern. But how to replace the '.*' with one space?

标签： vim

Answer 1

如果只想匹配正则表达式的一部分，可以使用\zs(start of match) 和\ze(end of match) 表达式：之前\zs和之后的匹配部分\ze将被丢弃，因此内部匹配将被替换：

s/orderNumber: \d\+\zs.*\zeorderID/ /

有关其他详细信息，请参阅:help \zs。