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问题描述

[注意:如果这很重要,我正在使用 3.1。另外,我在 codereview 上问过这个问题,但到目前为止没有任何回应。]

我需要一个运算符来允许布尔值流充当另一个流的门(当门流为真时让值通过,当门流为假时丢弃它们)。我通常会为此使用 Switch,但如果源流很冷,它将继续重新创建它,这是我不想要的。

我也想自己清理一下,以便在源或门完成时结果完成。

public static IObservable<T> When<T>(this IObservable<T> source, IObservable<bool> gate)
{
    var s = source.Publish().RefCount();
    var g = gate.Publish().RefCount();

    var sourceCompleted = s.TakeLast(1).DefaultIfEmpty().Select(_ => Unit.Default);
    var gateCompleted = g.TakeLast(1).DefaultIfEmpty().Select(_ => Unit.Default);

    var anyCompleted = Observable.Amb(sourceCompleted, gateCompleted);

    var flag = false;
    g.TakeUntil(anyCompleted).Subscribe(value => flag = value);

    return s.Where(_ => flag).TakeUntil(anyCompleted);
}

除了整体冗长之外,我不喜欢订阅门,即使结果从未订阅(在这种情况下,此运算符应该是无操作的)。有没有办法摆脱那个订阅?

我也尝试过这种实现,但在自行清理时更糟糕:

return Observable.Create<T>(
    o =>
    {
        var flag = false;
        gate.Subscribe(value => flag = value);

        return source.Subscribe(
            value =>
            {
                if (flag) o.OnNext(value);
            });
    });

这些是我用来检查实现的测试:

[TestMethod]
public void TestMethod1()
{
    var output = new List<int>();

    var source = new Subject<int>();
    var gate = new Subject<bool>();

    var result = source.When(gate);
    result.Subscribe(output.Add, () => output.Add(-1));

    // the gate starts with false, so the source events are ignored
    source.OnNext(1);
    source.OnNext(2);
    source.OnNext(3);
    CollectionAssert.AreEqual(new int[0], output);

    // setting the gate to true will let the source events pass
    gate.OnNext(true);
    source.OnNext(4);
    CollectionAssert.AreEqual(new[] { 4 }, output);
    source.OnNext(5);
    CollectionAssert.AreEqual(new[] { 4, 5 }, output);

    // setting the gate to false stops source events from propagating again
    gate.OnNext(false);
    source.OnNext(6);
    source.OnNext(7);
    CollectionAssert.AreEqual(new[] { 4, 5 }, output);

    // completing the source also completes the result
    source.OnCompleted();
    CollectionAssert.AreEqual(new[] { 4, 5, -1 }, output);
}

[TestMethod]
public void TestMethod2()
{
    // completing the gate also completes the result
    var output = new List<int>();

    var source = new Subject<int>();
    var gate = new Subject<bool>();

    var result = source.When(gate);
    result.Subscribe(output.Add, () => output.Add(-1));

    gate.OnCompleted();
    CollectionAssert.AreEqual(new[] { -1 }, output);
}

标签: c#system.reactive

解决方案


这有效:

public static IObservable<T> When<T>(this IObservable<T> source, IObservable<bool> gate)
{
    return
        source.Publish(ss => gate.Publish(gs =>
            gs
                .Select(g => g ? ss : ss.IgnoreElements())
                .Switch()
                .TakeUntil(Observable.Amb(
                    ss.Select(s => true).Materialize().LastAsync(),
                    gs.Materialize().LastAsync()))));
}

这通过了两项测试。


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