django - factory_boy:为一个相关工厂传递模型实例
问题描述
我认为与其将数据以 的形式传递给工厂的 RelatedFactory,不如ATTR__SUBATTR
直接传递已经存在的实例。除非我遗漏了一些非常明显的东西,否则这似乎不起作用。看一看:
class Owner(models.Model):
name = models.CharField()
class Item(models.Model):
name = models.CharField()
owner = models.ForeignKey(Owner, null = True, related_name = 'items')
class ItemFactory(factory.django.DjangoModelFactory):
class Meta:
model = Item
class OwnerFactory(factory.django.DjangoModelFactory):
class Meta:
model = Owner
items = factory.RelatedFactory(ItemFactory, 'owner')
item = Item.objects.create(name='Foo')
alice = OwnerFactory(name='Alice', items__name='Bar')
alice.items.all()
<QuerySet [<Item: Bar>]>
bob = OwnerFactory(name='Bob', items=item) # or items = [item] doesn't matter
bob.items.all()
<QuerySet []>
一直在努力让我的工厂变得漂亮和干燥,并遇到了这个障碍。写了我自己的改编版RelatedFactory
,允许一次处理多个值,如果您在该过程中创建新对象,这可以正常工作 - 但如果您正在使用已经存在的对象,则不会。
有效的例子:OwnerFactory(items__name=['Foo','Bar'])=> Foo and Bar in owner.items
.
不起作用的示例:OwnerFactory(items=[foo,bar])=> owner.items is empty
请注意,我在顶部的大示例中使用了默认的 RelatedFactory。
我一整天都在翻阅 factory_boy 的文档,但找不到解决方案,现在狭隘的视野已经接管了,禁止任何新的见解。
解决方案
您正在寻找http://factoryboy.readthedocs.io/en/latest/recipes.html#simple-many-to-many-relationship
class ItemFactory(factory.django.DjangoModelFactory):
class Meta:
model = Item
class OwnerFactory(factory.django.DjangoModelFactory):
class Meta:
model = Owner
@factory.post_generation
def items(self, create, extracted, **kwargs):
if not create:
# Simple build, do nothing.
return
if extracted:
# A list of items were passed in, use them
for item in extracted:
self.items.add(item)
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