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python - 使用变量内的列表

问题描述

我遇到的这个问题是我不能使用我刚刚创建并存储在 current_pizza_list 中的列表。

pizza_1 = ['8.00','Pepperoni']
print('Input 1 for ', pizza_1[1])
current_pizza = input('What pizza would you like:')
current_pizza_list = ('pizza_' + str(current_pizza) + '[1]')
pizza_ammount = input('How many', str(current_pizza_list) ,' pizzas would you like:')

标签： python

解决方案

num = 5 
pizza_name = 'pizza_' + str(num)
print('Our pizza choices are ' + pizza_name + '!')
#What you created above is a variable. That is not a list. Below is a list:
#pizzas = ['pepperoni', 'extra cheese', 'cheese', 'veggie']
current_pizza = input('What pizza would you like: ')
current_pizza_name = ('pizza_' + str(current_pizza) + '[1]')
pizza_ammount = int(input('How many ' + current_pizza_name + "'s would you like?: "))
print('You would like ' + str(pizza_ammount) + ' ' + current_pizza_name + ' pizzas!')

这是您的输出：

Our pizza choices are pizza_5!
What pizza would you like: 5
How many pizza_5[1]'s would you like?: 10
You would like 10 pizza_5[1] pizzas!

现在你已经声明你想要一个列表，但在你的例子中没有列表，所以我不确定你的意思，但下面是一个披萨列表的例子，并在我们访问后为每个披萨附加一个数字它：

pizza_list = [1, 2, 3, 4, 5, 6, 7, 8]
print('Our pizza choices are: ')
for pizza in pizza_list:
    print('\t' + str(pizza))

pizza_choice = int(input('Which pizza would you like to select?: '))
if pizza_choice in pizza_list:
    current_pizza = 'pizza_' + str(pizza_choice)

else:
   print('We do not have that pizza')

pizza_amount = int(input('How many ' + current_pizza + "'s would you like?: "))
print('You would like ' + str(pizza_amount) + ' ' + current_pizza + " pizza's.")

上面我们有一个列表，我在您的代码示例中没有看到它，称为比萨饼列表。如果用户在列表中选择了一个披萨，我们可以将该披萨编号附加到 Pizza_ 字符串的末尾。然后我们询问用户他们想要多少披萨。Pizza_list 可以作为您的列表。这是输出：

Our pizza choices are: 
1
2
3
4
5
6
7
8
Which pizza would you like to select?: 5
How many pizza_5's would you like?: 20
You would like 20 pizza_5 pizza's.

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