scala - Scala 中的伴随对象和类访问
问题描述
假设我有这个类和对象层次结构:
class A extends BB
class B extends BB
object A extends BB
abstract class BB {
def writer: Writer (<say Writer is a custom class>)
def write: {
writer.<dothing>
}
}
因此 writer 必须在类中实现,A
而B
不是在对象 A 中实现,这样代码才能正常工作。正确的?
new A.write
new B.write
因此 writer 必须在对象 A 中实现才能使此代码正常工作。正确的?
A.write
解决方案
trait : 是无状态的,class
或者object
两者都可以扩展trait
。
您将某物定义为object
它没有任何状态。
scala> trait CanFly {
| def fly: String
| }
defined trait CanFly
scala> class DuckCanFly extends CanFly {
| override def fly: String = "duck duck"
| }
defined class DuckCanFly
scala> object EagleCanFly extends CanFly {
| override def fly: String = "eagle eagle"
| }
defined object EagleCanFly
scala> new DuckCanFly().fly
res0: String = duck duck
scala> EagleCanFly.fly
res1: String = eagle eagle
如果您希望伴随对象将其定义如下,则不必再次扩展该特征。
scala> :paste
// Entering paste mode (ctrl-D to finish)
class DuckCanFly extends CanFly {
override def fly: String = "duck duck"
}
object DuckCanFly {
def apply(): DuckCanFly = new DuckCanFly()
}
// Exiting paste mode, now interpreting.
defined class DuckCanFly
defined object DuckCanFly
scala> DuckCanFly().fly
res8: String = duck duck
在您的示例中,您可以将其定义trait
为我没有看到任何状态,并且您可以将孩子定义为object
.
trait BB {
def writer: Writer
def write = writer.write()
}
object A extends BB {
def writer: Writer = new AWriter()
}
object B extends BB {
def writer: Writer = new BWriter()
}