laravel - Laravel 5.6 中的策略

Question

我正在尝试policy在我的Laravel 5.6应用程序中进行访问级别控制。

我有一个Subscriber模型和一个Company模型，Subscribers只能Company由那里的办公室位置根据 访问states/region，即如果办公室属于分配给他们的区域，订户可以查看办公室的详细信息。为此，我有模型：

订户

class Subscriber extends Model {

    //Fillables and basic attributes being assigned

    public function stateIncludeRelation()
    {
        return  $this->belongsToMany('Models\State','subscriber_states',
            'subscriber_id', 'state_id');
    }

    public function user()
    {
        return $this->belongsTo('Models\User', 'user_id', 'id');
    }
}

公司

class Company extends Model {

    //Fillables and basic attributes being assigned

    public function offices()
    {
        return $this->hasMany('Models\Company\Office', 'company_id');
    }
}

然后为办公室

class Office extends Model {

    //Fillables and basic attributes being assigned

    public function company()
    {
        return $this->belongsTo('Models\Company', 'company_id', 'id');
    }}
}

和一个常见的状态表：

class State extends Model {

    //Fillables and basic attributes being assigned

    public function subscriberAccess()
    {
        return $this->belongsToMany('Models\Subscriber',
            'subscriber_states_included_relation',
            'state_id', 'subscriber_id');
    }

    public function companyOffice()
    {
        return $this->hasOne('Models\Company\Office', 'state', 'id');
    }
}

我创建了一个像这样的CompanyPolicy ：

class CompanyPolicy
{
    use HandlesAuthorization;

    /**
     * Determine whether the user can view the subscriber.
     *
     * @param User $user
     * @param Company $company
     * @return mixed
     */
    public function view(User $user, Company $company)
    {
        //Finding subscriber/user state
        $userState = State::whereHas('subscriberAccess', function ($q) use($user) {
            $q->whereHas('user', function ($q) use($user) {
                $q->where('email', $user->email);
            });
        })->get()->pluck('name');

        //Finding company state
        $companyState = State::whereHas('companyOffice', function ($q) use($company) {
            $q->whereHas('company', function ($q) use($company) {
                $q->where('slug', $company->slug);
            });
        })->get()->pluck('name');

        if($userState->intersect($companyState)->all())
            return true;
        else
            return false;
    }
}

并将其注册到AuthServiceProvider

protected $policies = [
    'App\Model' => 'App\Policies\ModelPolicy',
    'Models\User' => 'Policies\CompanyPolicy',
];

在我的控制器中尝试获取类似的东西时：

public function companyGeneral(Request $request)
{
    $user = Auth::user();

    $company = Company::where('slug', $request->slug)
        ->with('offices')
        ->get()->first();

    if($user->can('view', $company))
        return response()->json(['data' => $company], 200);
    else
        return response()->json(['data' => 'Unauthorised'], 403);
}

每次我收到未经授权的回复。引导我进入这个。谢谢

标签： laravellaravel-5.6laravel-authorization