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首页 > 解决方案 > 如何在 Qt 中获取指向弹出对话框的指针，这会阻止 QTest 中的 UI 线程

c++ - 如何在 Qt 中获取指向弹出对话框的指针，这会阻止 QTest 中的 UI 线程

问题描述

我正在使用 QTest 编写一个集成测试，其中只要我单击小部件的视口，就会出现一个多行弹出 QInputDialog，它会阻止代码的进一步执行并需要手动取消对话框。这是代码： 

void PartTest::testTypewriterAnnotTool()
{
    Okular::Part part(nullptr, nullptr, QVariantList()); // It is the main widget of PDF reader comprising of viewport where PDF page is shown

    part.openUrl(QUrl::fromLocalFile(QStringLiteral(KDESRCDIR "data/file1.pdf"))); // open file1.pdf

    part.widget()->show();
    QVERIFY(QTest::qWaitForWindowExposed(part.widget()));

    // Width and height of pageView widget, the child of Part widget which shows the PDF page

    const int width = part.m_pageView->horizontalScrollBar()->maximum() +
                      part.m_pageView->viewport()->width();
    const int height = part.m_pageView->verticalScrollBar()->maximum() +
                       part.m_pageView->viewport()->height();

    part.m_document->setViewportPage(0); // sets viewport page 0, i.e. page number 1

    QMetaObject::invokeMethod(part.m_pageView, "slotToggleAnnotator", Q_ARG( bool, true )); // toggles and shows the annotation toolbar with all tools avaialable

    QList<QToolButton *> toolbuttonList = part.m_pageView->findChildren<QToolButton *>(); // find a list of annotation toolbutton
    // Check if the tooltip of 10th button is "Typewriter"
    QToolButton* typewriterButton = toolbuttonList.at(9);
    QCOMPARE( typewriterButton->toolTip(), QStringLiteral("Typewriter") );

    typewriterButton->click(); // clicking and selecting typewriter annotation tool

    QTest::mouseMove(part.m_pageView->viewport(), QPoint(width * 0.5, height * 0.2)); // leading mouse pointer to a specific point in the viewport

    QTest::mouseClick(part.m_pageView->viewport(), Qt::LeftButton, Qt::NoModifier, QPoint(width * 0.5, height * 0.2)); // mouse left button click on the viewport and a popup dialog with 'add a new note' appears

}

我必须编写一个测试用例，我必须抓住那个弹出对话框并以编程方式关闭它。我试图通过使用 QTimer 来实现这一点，我将在其中执行一个函数以在单击视口 1 秒后抓取对话框，然后尝试像这样关闭它：

class PartTest
{
...
private:
    Okular::part *m_part;
}

void PartTest::testTypewriterAnnotTool()
{
...
    m_part = &part;
    QTimer* mTimer = new QTimer(this);
    mTimer->setSingleShot(true);
    connect(mTimer, SIGNAL(timeout()), SLOT(testDialogClosed()));
    mTimer->start(1000);
    QTest::mouseClick(part.m_pageView->viewport(), Qt::LeftButton, Qt::NoModifier, QPoint(width * 0.5, height * 0.2));
}

void PartTest::testDialogClosed()
{
    bool m_clicked = false;
    QDialog *dialog = m_part->widget()->findChild<QDialog*>();
    if (dialog)
    {
        QDialogButtonBox *buttonBox = dialog->findChild<QDialogButtonBox*>();
        buttonBox->button(QDialogButtonBox::Cancel)->click();
        m_clicked = true;
    }
    QVERIFY(m_clicked);
}

在这里，QVERIFY(m_clicked)测试用例总是“失败”，这意味着弹出窗口QInputDialog is not the child of Okular::Part，我没有办法抓住指向这个对话框窗口的指针并关闭它。有什么帮助吗？

标签： c++qtunit-testingtestingintegration-testing

解决方案

您可以枚举顶级小部件并以这种方式找到对话框：

template <class P> QList<P> topLevelWidgets() {
  QList<P> widgets
  for (auto *w : QApplication::topLevelWidgets())
    if (auto *t = qobject_cast<P>(w))
      widgets << t;
  return widgets;
}

template <class P> P topLevelWidget() {
  auto w = topLevelWidgets<P>();
  return (w.size() == 1) ? w.first() : nullptr;
}

void PartTest::testDialogClosed()
{
    bool m_clicked = false;
    if (auto *dialog = topLevelWidget<QDialog*>())
      if (auto *buttonBox = dialog->findChild<QDialogButtonBox*>()) {
        buttonBox->button(QDialogButtonBox::Cancel)->click();
        m_clicked = true;
      }
    QVERIFY(m_clicked);
}

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