javascript - 语法错误是什么,为什么非活跃玩家会被计分
问题描述
我正在构建一个简单的骰子游戏。我在计算非活跃玩家的分数时遇到问题。当它切换玩家时,它仍然计入未激活的玩家。我看了很多遍,就是找不到。我什至稍稍休息了一下,向前移动了一点,然后回来了,仍然找不到。这是我的代码。
var scores, roundScore, activePlayer;
scores = [0, 0];
roundScore = 0;
activePlayer = 1;
document.querySelector('.dice').style.display = 'none';
document.getElementById('score-0').textContent = '0';
document.getElementById('score-1').textContent = '0';
document.getElementById('current-0').textContent = '0';
document.getElementById('current-1').textContent = '0';
document.querySelector('.btn-roll').addEventListener('click', function
() {
//ran. number
var dice = Math.floor(Math.random() * 6) + 1;
// displaying result
var diceDom = document.querySelector('.dice');
diceDom.style.display = 'block';
diceDom.src = 'Assets/dice-' + dice + '.png';
// update round score IF the rolled # was not a 1
if (dice !== 1) {
roundScore += dice;
document.querySelector('#current-' + activePlayer).textContent =
roundScore;
} else {
//go to next player
nextPlayer();
}
});
document.querySelector('.btn-hold').addEventListener('click', function()
{
// add current score to global
scores[activePlayer] += roundScore;
//update UI
document.querySelector('#score-' + activePlayer).textContent =
scores[activePlayer];
//check if player won the game
//next player
nextPlayer();
});
function nextPlayer() {
//go to next player
activePlayer === 0 ? activePlayer = 1 : activePlayer = 0;
roundScore = 0;
document.getElementById('current-0').textContent = '0';
document.getElementById('current-1').textContent = '0';
document.querySelector('.player-0-
panel').classList.toggle('active');
document.querySelector('.player-1-
panel').classList.toggle('active');
//hide dice when player rolls 1
document.querySelector('.dice').style.display = 'none';
}
解决方案
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