首页 > 解决方案 > 带有目标c的Xcode将json数据发布到php api

问题描述

我试图将一些用户数据从 ios 发布到我的 php api,但接收到的数据未正确格式化为 json 文件。请有人可以帮助我,因为我对 ios 和目标 c 非常陌生。

这是我的 php 示例

<?php 
if(isset($_REQUEST['data']) ){
    if(!empty($_REQUEST['data']) && strlen($_REQUEST['data']) > 3){
        $api_data = $_REQUEST['data'];
        $json_data = json_decode($api_data, true);
        $hash_key = md5($api_data);
        $post_var  = array(
            'date' => date('m-d-Y h:m:sA'),
        );
        $post_var  = '{"apiData":'.$api_data.', "moreData":'.json_encode($post_var).'}';
        $readTheApis = __DIR__ . '/cdn/api_request_note.txt';
        $handl_log = fopen($readTheApis, "a+") or die("Failed to create log");
        $addlog = fwrite($handl_log, $post_var. "\r\n");
        fclose($handl_log);
        foreach ($json_data as $key => $val) {
            echo $key . ' | ' . $val;
        }
    }
}

目标 C

-(void)HitAPI{

    [SVProgressHUD showWithStatus:@"Wait.."];

    NSDictionary *jsonUserDictionary = [NSDictionary dictionaryWithObjectsAndKeys:
        Str_LatPost, @"lat",
        Str_LongPost, @"long",
        [[FIRInstanceID instanceID] token], @"fcmtoken",
        [[UIDevice currentDevice] name], @"device",
        deviceName(), @"device_type",
        [[NSUserDefaults standardUserDefaults] valueForKey:@"pref_mytoken"], @"deviceid",
        @"FRaVY4cXVoVjA", @"key", nil];

    NSMutableArray *mutArrData = [NSMutableArray array];
    [mutArrData addObject:jsonUserDictionary];

    NSString*StrPost = [NSString stringWithFormat:@"data=%@",mutArrData];
    NSString *jsonString = StrPost;
    jsonString = [jsonString stringByReplacingOccurrencesOfString:@" " withString:@""];
    jsonString = [jsonString stringByReplacingOccurrencesOfString:@"[" withString:@""];
    jsonString = [jsonString stringByReplacingOccurrencesOfString:@"]" withString:@""];
    NSData *postData = [jsonString dataUsingEncoding:NSASCIIStringEncoding allowLossyConversion:YES];
    NSMutableURLRequest *request = [[NSMutableURLRequest alloc] init];

    [request setURL:[NSURL URLWithString:[
      NSString stringWithFormat:@"https://example.com/app/1d54f4dax/api.php?data"
      ]]];

    [request setHTTPMethod:@"POST"];
    [request setHTTPBody:postData];

    /*
     BECUSE OF DEPRECIATE WARNING I ADDED THE BELOW CODE BUT AM NOT SURE IF IT WILL WORK
     NSURLConnection *theConnection = [[NSURLConnection alloc] initWithRequest:request delegate:self];
    [theConnection start];*/


    NSURLSession *session = [NSURLSession sharedSession];
    NSURLSessionDataTask *theConnection = [session dataTaskWithRequest:request completionHandler:^(NSData *data, NSURLResponse *response, NSError *error){
        // do something with the data'
    }];
    [theConnection resume];
}

当前结果

{设备=iPhone;"device_type"="iPhone6"; 设备ID=f2cd64;fcmtoken="9exBTN7FSfg"; 键=XVoVjA;lat="2.90909862"; long="101.897877"; }

预期结果

{ “设备”:“iPhone”,“device_type”:“iPhone6”,“deviceid”:“f2cd64”,“fcmtoken”:“9exBTN7FSfg”,“key”:“XVoVjA”,“lat”:“2.90909862”,“长":"101.897877" }

标签: phpobjective-cjsonxcodeapi

解决方案


嗯,看起来很复杂。您正在将您的 jsonUserDictionary 嵌入到其他字典中,并且在您需要删除[]...之后尝试这个简单的方法:

NSError *writeError = nil;
NSData  *jsonData   = [NSJSONSerialization dataWithJSONObject: jsonUserDictionary options:NSJSONWritingPrettyPrinted error:&writeError];
if (writeError) {
    NSLog(@"Write error : %@", [writeError description]);
}
NSString *jsonString = [[[NSString alloc] initWithData:jsonData encoding:NSUTF8StringEncoding] stringByRemovingPercentEncoding];
// now send this


[request setHTTPMethod:@"POST"];
[request setHTTPBody:[postString dataUsingEncoding:NSUTF8StringEncoding]];
[resuest setValue:@"application/json" forHTTPHeaderField:@"Content-Type"];

// get rid of apple dogma

#pragma clang diagnostic push
#pragma clang diagnostic ignored "-Wdeprecated-declarations"
_urlConnection = [[NSURLConnection alloc] initWithRequest:request
                                                 delegate:self];

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