首页 > 解决方案 > 无状态组件 React 路由器

问题描述

我是 React 和 Redux 的新手,我实际上是在创建自己的代码,但我在无状态组件中遇到了路由器之类的东西。

所以,实际上我需要使用 this.props.history.push('/somepath') 来路由到一个组件。这不会发生在无状态组件内部。

我的无状态组件是

import React from "react"; // eslint-disable-line no-unused-vars
import "bootstrap/dist/css/bootstrap.min.css";
import "./header.css";

const Header = () => ({

    handleAuthor() {
        this.props.history('/somepath')// this is not working
    },

    render(){
        return (
            <div className = "header">
                <h1 onClick = {this.handleAuthor.bind(this)}>{this.props.headerText}</h1>
            </div>
        );
    } 
});

export default Header;

我在另一个无状态组件中调用它,比如 mainlayout

import React from "react"; // eslint-disable-line no-unused-vars
import Header from "../header/Header"; // eslint-disable-line no-unused-vars
import Footer from "../footer/Footer"; // eslint-disable-line no-unused-vars
import "./mainLayout.css";

const MainLayout = props => ({
    render() {
        return (
            <div className="App">
                <Header headerText = "RK Boilerplate"/>
                <div className = "mainLayout">
                    <main>{props.children}</main>
                </div>
                <Footer />
            </div>
        );
    }
});

export default MainLayout;

我的主文件 index.js 看起来像这样

import React from "react"; // eslint-disable-line no-unused-vars
import ReactDOM from "react-dom"; // eslint-disable-line no-unused-vars
import { matchRoutes, renderRoutes } from "react-router-config"; // eslint-disable-line no-unused-vars
import { Router } from "react-router-dom"; // eslint-disable-line no-unused-vars
import { Switch } from "react-router"; // eslint-disable-line no-unused-vars
import { Provider } from "react-redux"; // eslint-disable-line no-unused-vars
import store from "./store"; // eslint-disable-line no-unused-vars
import routes from "./routes"; // eslint-disable-line no-unused-vars
import MainLayout from "./components/mainLayout/MainLayout"; // eslint-disable-line no-unused-vars

import createHistory from "history/createBrowserHistory";
let history = createHistory();
const App =  document.getElementById("app");

export default App;

ReactDOM.render(
    <Provider store={store}>
        <MainLayout>
            <Router history= {history}>
                <Switch>
                    {renderRoutes(routes)}
                </Switch>
            </Router>
        </MainLayout>                 
    </Provider>, 
    App);

所以我需要的是我必须从标题路由到另一个组件,该组件和路径在路由器文件中给出

路由器.js

import Home from "../containers/Home";
import About from "../containers/About";
import CreateUser from "../containers/CreateUser";

import Layout from "../containers/Layout";

const routes = [
    { path: "/",
        exact: true,
        component: Layout
    },
    { path: "/home",
        exact: true,
        component: Home
    },
    {
        path:"/About",
        exact: true,
        component: About
    },
    {
        path:"/createUser",
        exact: true,
        component: CreateUser
    }
];

export default routes;

当我尝试从标头路由时,出现类似 push of undefined 的错误。我是否遗漏了什么我应该在这里做的任何改变。

提前致谢。

标签: reactjsreduxreact-routerreact-router-v4react-component

解决方案


2019 年,React Router v4 现在为无状态/功能组件添加了 useHistory 钩子:

https://reacttraining.com/react-router/web/api/Hooks/usehistory

从文档:

import { useHistory } from "react-router-dom";

function HomeButton() {
  let history = useHistory();

  function handleClick() {
    history.push("/home");
  }

  return (
    <button type="button" onClick={handleClick}>
      Go home
    </button>
  );
}

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