reactjs - 无状态组件 React 路由器
问题描述
我是 React 和 Redux 的新手,我实际上是在创建自己的代码,但我在无状态组件中遇到了路由器之类的东西。
所以,实际上我需要使用 this.props.history.push('/somepath') 来路由到一个组件。这不会发生在无状态组件内部。
我的无状态组件是
import React from "react"; // eslint-disable-line no-unused-vars
import "bootstrap/dist/css/bootstrap.min.css";
import "./header.css";
const Header = () => ({
handleAuthor() {
this.props.history('/somepath')// this is not working
},
render(){
return (
<div className = "header">
<h1 onClick = {this.handleAuthor.bind(this)}>{this.props.headerText}</h1>
</div>
);
}
});
export default Header;
我在另一个无状态组件中调用它,比如 mainlayout
import React from "react"; // eslint-disable-line no-unused-vars
import Header from "../header/Header"; // eslint-disable-line no-unused-vars
import Footer from "../footer/Footer"; // eslint-disable-line no-unused-vars
import "./mainLayout.css";
const MainLayout = props => ({
render() {
return (
<div className="App">
<Header headerText = "RK Boilerplate"/>
<div className = "mainLayout">
<main>{props.children}</main>
</div>
<Footer />
</div>
);
}
});
export default MainLayout;
我的主文件 index.js 看起来像这样
import React from "react"; // eslint-disable-line no-unused-vars
import ReactDOM from "react-dom"; // eslint-disable-line no-unused-vars
import { matchRoutes, renderRoutes } from "react-router-config"; // eslint-disable-line no-unused-vars
import { Router } from "react-router-dom"; // eslint-disable-line no-unused-vars
import { Switch } from "react-router"; // eslint-disable-line no-unused-vars
import { Provider } from "react-redux"; // eslint-disable-line no-unused-vars
import store from "./store"; // eslint-disable-line no-unused-vars
import routes from "./routes"; // eslint-disable-line no-unused-vars
import MainLayout from "./components/mainLayout/MainLayout"; // eslint-disable-line no-unused-vars
import createHistory from "history/createBrowserHistory";
let history = createHistory();
const App = document.getElementById("app");
export default App;
ReactDOM.render(
<Provider store={store}>
<MainLayout>
<Router history= {history}>
<Switch>
{renderRoutes(routes)}
</Switch>
</Router>
</MainLayout>
</Provider>,
App);
所以我需要的是我必须从标题路由到另一个组件,该组件和路径在路由器文件中给出
路由器.js
import Home from "../containers/Home";
import About from "../containers/About";
import CreateUser from "../containers/CreateUser";
import Layout from "../containers/Layout";
const routes = [
{ path: "/",
exact: true,
component: Layout
},
{ path: "/home",
exact: true,
component: Home
},
{
path:"/About",
exact: true,
component: About
},
{
path:"/createUser",
exact: true,
component: CreateUser
}
];
export default routes;
当我尝试从标头路由时,出现类似 push of undefined 的错误。我是否遗漏了什么我应该在这里做的任何改变。
提前致谢。
解决方案
2019 年,React Router v4 现在为无状态/功能组件添加了 useHistory 钩子:
https://reacttraining.com/react-router/web/api/Hooks/usehistory
从文档:
import { useHistory } from "react-router-dom";
function HomeButton() {
let history = useHistory();
function handleClick() {
history.push("/home");
}
return (
<button type="button" onClick={handleClick}>
Go home
</button>
);
}
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