php - PHP Check Url and detect empty parameters parts

Question

I Have Url structure for multi language system like this:

for default language ie: en

localhost/cms

And Another Language Like:

localhost/cms/fr

localhost/cms/de

localhost/cms/es

Now I have this function for detect empty url language short name parts and set to default language:

function urlss(){

    $uri = $_SERVER['REQUEST_URI'];

    $languages = ['en', 'fr', 'es', 'de'];

    // this is my default language
    $defaultLang = 'en';

    // $currentLang is the language I'll use to show the contents
    $currentLang = $defaultLang;

    $uri = ltrim(rawurldecode($uri), '/');
    $parts = explode('/', $uri);

    if( ! empty($parts) && in_array(strtolower($parts[0]), $languages)) {
        $currentLang = array_shift($parts);
    }

    $routableUri = implode('/', $parts);

return $routableUri;

}

Check in Url: localhost/cms/ and Output Is: cms/ and not work true.

In action I need to check My url, if not detect language short name ie: en default language = en and then put in session or cookie But if detect language short name ie: fr es de set session or cookie to this language.

How do can I fix my problem and check my url for language short name?!

标签： phpparameters

Answer 1

I would approach this problem using a regular expression.

// Prepare request URI, available languages and default language
$url = $_SERVER['REQUEST_URI'];
$languages = ['en', 'fr', 'es', 'de'];
$default = 'en';

// Build regular expression and attempt to match language in URL
preg_match('/^\/cms\/(' . implode('|', $languages) . ')\//', $url, $match);

// Set language to match or default to English
$language = $match[1] ?? $default;

// Remove default language from URL
$url = preg_replace("/\/{$default}/", '', $url);