c# - 在新桌面中启动进程

Question

我正在尝试在新桌面上启动一个进程。

这是我到目前为止的代码，但它会在后台打开进程。

新桌面完美创建。所以这一切都很好。

但是，新进程不会在新桌面中打开。

我需要把外部进程放到前面或者在新桌面打开

关于在新桌面中启动该过程，我在哪里做错了？

你能帮忙吗？

感谢您的任何意见

using System;
using System.Drawing;
using System.Runtime.InteropServices;
using System.Threading.Tasks;
using System.Windows.Forms;
using System.Diagnostics;

namespace AntiKeylogger
{
  //  public partial class Program : NetkioskVDesktop.Form1
 //   public partial class Program :

static class Program
{

    [DllImport("user32.dll")]
    public static extern IntPtr CreateDesktop(string lpszDesktop, IntPtr lpszDevice, IntPtr pDevmode, int dwFlags, uint dwDesiredAccess, IntPtr lpsa);

    [DllImport("user32.dll")]
    private static extern bool SwitchDesktop(IntPtr hDesktop);

    [DllImport("user32.dll")]
    public static extern bool CloseDesktop(IntPtr handle);

    [DllImport("user32.dll")]
    public static extern bool SetThreadDesktop(IntPtr hDesktop);

    [DllImport("user32.dll")]
    public static extern IntPtr GetThreadDesktop(int dwThreadId);

    [DllImport("kernel32.dll")]
    public static extern int GetCurrentThreadId();

   enum DESKTOP_ACCESS : uint

   {
        DESKTOP_NONE = 0,
        DESKTOP_READOBJECTS = 0x0001,
        DESKTOP_CREATEWINDOW = 0x0002,
        DESKTOP_CREATEMENU = 0x0004,
        DESKTOP_HOOKCONTROL = 0x0008,
        DESKTOP_JOURNALRECORD = 0x0010,
        DESKTOP_JOURNALPLAYBACK = 0x0020,
        DESKTOP_ENUMERATE = 0x0040,
        DESKTOP_WRITEOBJECTS = 0x0080,
        DESKTOP_SWITCHDESKTOP = 0x0100,

        GENERIC_ALL = (DESKTOP_READOBJECTS | DESKTOP_CREATEWINDOW | DESKTOP_CREATEMENU |
                        DESKTOP_HOOKCONTROL | DESKTOP_JOURNALRECORD | DESKTOP_JOURNALPLAYBACK |
                        DESKTOP_ENUMERATE | DESKTOP_WRITEOBJECTS | DESKTOP_SWITCHDESKTOP),
    }


     [DllImport("kernel32.dll")]
     private static extern bool CreateProcess(
       string lpApplicationName,
       string lpCommandLine,
       IntPtr lpProcessAttributes,
       IntPtr lpThreadAttributes,
       bool bInheritHandles,
       int dwCreationFlags,
       IntPtr lpEnvironment,
       string lpCurrentDirectory);


    static void Main(string[] args)
    {

      IntPtr hOldDesktop = GetThreadDesktop(GetCurrentThreadId());
      IntPtr hNewDesktop = CreateDesktop("RandomDesktopName", IntPtr.Zero, IntPtr.Zero, 0, (uint)DESKTOP_ACCESS.GENERIC_ALL, IntPtr.Zero);

        SwitchDesktop(hNewDesktop);     

        Task.Factory.StartNew(() =>

        {
          SetThreadDesktop(hNewDesktop);

          Application.EnableVisualStyles();
          Application.SetCompatibleTextRenderingDefault(false);
          Application.Run(new NetkioskVDesktop.Form1());

         Process.Start("C:\\Windows\\System32\\Notepad.exe");


        }).Wait(); 
        SwitchDesktop(hOldDesktop);    
        CloseDesktop(hNewDesktop);

    }
}

}

标签： c#processdesktop

Answer 1

    [DllImport("user32.dll")]
    public static extern IntPtr CreateDesktop(string lpszDesktop, IntPtr lpszDevice, IntPtr pDevmode, int dwFlags, uint dwDesiredAccess, IntPtr lpsa);

    [DllImport("user32.dll")]
    private static extern bool SwitchDesktop(IntPtr hDesktop);

    [DllImport("user32.dll")]
    public static extern bool CloseDesktop(IntPtr handle);

    [DllImport("user32.dll")]
    public static extern bool SetThreadDesktop(IntPtr hDesktop);

    [DllImport("user32.dll")]
    public static extern IntPtr GetThreadDesktop(int dwThreadId);

    [DllImport("kernel32.dll")]
    public static extern int GetCurrentThreadId();

    enum DesktopAccess : uint
    {
        DesktopReadobjects = 0x0001,
        DesktopCreatewindow = 0x0002,
        DesktopCreatemenu = 0x0004,
        DesktopHookcontrol = 0x0008,
        DesktopJournalrecord = 0x0010,
        DesktopJournalplayback = 0x0020,
        DesktopEnumerate = 0x0040,
        DesktopWriteobjects = 0x0080,
        DesktopSwitchdesktop = 0x0100,

        GenericAll = DesktopReadobjects | DesktopCreatewindow | DesktopCreatemenu |
                     DesktopHookcontrol | DesktopJournalrecord | DesktopJournalplayback |
                     DesktopEnumerate | DesktopWriteobjects | DesktopSwitchdesktop
    }

    public Form1()
    {
        InitializeComponent();
    }

    //You must press this button to start
    private void btnInit_Click(object sender, EventArgs e)
    {
        Init();
    }

    private static void Init()
    {
        // old desktop's handle, obtained by getting the current desktop assigned for this thread
        var hOldDesktop = GetThreadDesktop(GetCurrentThreadId());

        // new desktop's handle, assigned automatically by CreateDesktop
        var hNewDesktop = CreateDesktop(GetRandomName(), IntPtr.Zero, IntPtr.Zero, 0, (uint)DesktopAccess.GenericAll, IntPtr.Zero);

        // switching to the new desktop
        SwitchDesktop(hNewDesktop);

        // Random login form: used for testing / not required
        var passwd = "";

        // running on a different thread, this way SetThreadDesktop won't fail
        Task.Factory.StartNew(() =>
        {
            // assigning the new desktop to this thread - so the Form will be shown in the new desktop)
            SetThreadDesktop(hNewDesktop);

            var inbox = new CustomInbox();
            inbox.FormClosing += (sender, e) => { passwd = inbox.Value; };

            Application.Run(inbox);


        }).Wait();  // waits for the task to finish
        // end of login form

        // if got here, the form is closed => switch back to the old desktop
        SwitchDesktop(hOldDesktop);

        // disposing the secure desktop since it's no longer needed
        CloseDesktop(hNewDesktop);

        MessageBox.Show(@"Password, typed inside secure desktop: " + passwd, @"Notice", MessageBoxButtons.OK, MessageBoxIcon.Information);

    }

    //This get a random name for the new desktop
    private static string GetRandomName()
    {
        var value = DateTime.Now.ToLongTimeString();
        value = value.GetHashCode().ToString().Replace("-", "").ToLowerInvariant();
        return value;
    }