首页 > 解决方案 > data.push 不工作抽搐机器人

问题描述

function lfg(user){
    WTPLength = viewersWTP.length;
    if (WTPLength !== 0) {
        viewersWTP = viewersWTP - 1
        while(WTPLength !== -1){
            if(user === viewersWTP[WTPLength]){
                console.log("Already in list")
                client.action("kong_plays",user+" you cannot execute this command again until kong pulls a viewer to play with him!")
                fil = True;
            }else{
                WTPLength = WTPLength - 1;
            }
        }if (fil !== true){
            viewersWTP.push(user);
            console.log("Added into list")
            client.action("kong_plays",viewersWTP)
        }
    }else{        //here
        viewersWTP.push(user);
            console.log(viewersWTP)
            client.action("kong_plays","1"+viewersWTP)
    }
}

如果我运行代码两次,第一次在 while 之外的 else 中的代码(它说//here)工作但是第二次控制台输出:viewersWTP.push is not a function

提前致谢

标签: javascriptnode.jstwitch

解决方案


应该怎么viewersWTP = viewersWTP - 1做?这可能会将数组转换为NaN. 你也许是说WTPLength = WTPLength - 1

var a = [1, 2, 3];
console.log(a);
a = a - 1;
console.log(a);


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