时间戳

首页 > 解决方案 > 将字典列表分解为常用元素的字典

python - 将字典列表分解为常用元素的字典

问题描述

这个问题很难用标题来解释。

我有一个庞大的字典列表，dict_list，大约 18k 长。它们中的一个键是“PROCESS”。这两个过程是“Etch”和“Depo”，每个过程都会重复一段时间，然后切换到另一个，然后返回。这些被称为“运行”。

我需要将类似的流程组合到一个列表中，直到流程发生变化，然后将该列表插入到“运行”字典中。这是一个更好的视觉解释：

dict_list = [{"PROCESS": "Etch"},{"PROCESS": "Etch"},{"PROCESS": "Etch"},
             {"PROCESS": "Etch"},{"PROCESS": "Etch"},{"PROCESS": "Etch"},
             {"PROCESS": "Etch"},{"PROCESS": "Etch"},{"PROCESS": "Etch"},
             {"PROCESS": "Etch"},{"PROCESS": "Etch"},{"PROCESS": "Etch"},
             {"PROCESS": "Etch"},{"PROCESS": "Etch"},{"PROCESS": "Etch"},
             {"PROCESS": "Depo"},{"PROCESS": "Depo"},{"PROCESS": "Depo"},
             {"PROCESS": "Depo"},{"PROCESS": "Depo"},{"PROCESS": "Depo"},
             {"PROCESS": "Depo"},{"PROCESS": "Depo"},{"PROCESS": "Depo"},
             {"PROCESS": "Depo"},{"PROCESS": "Depo"},{"PROCESS": "Depo"},
             {"PROCESS": "Depo"},{"PROCESS": "Depo"},{"PROCESS": "Depo"},
             {"PROCESS": "Etch"},{"PROCESS": "Etch"},{"PROCESS": "Etch"},
             {"PROCESS": "Etch"},{"PROCESS": "Etch"}]

基本上，如果我循环dict_list，逐行打印每个“PROCESS”，它看起来像：

>>"Etch"
>>"Etch"
>>"Etch"
>>"Etch"
>>"Depo"
>>"Depo"
>>"Depo"
>>"Depo"
>>"Etch"
>>"Etch"
>>"Etch"
>>"Etch"
>>"Depo"
>>"Depo"
>>"Depo"
>>"Depo"

对于该示例，我将有 4 个“运行”字典，每个字典都有一个包含 4 个字典的列表。

我需要将它们分组到列表中，然后到这样的字典中：

new_dict_list = {
    "run 1": [{"PROCESS": "Etch"},{"PROCESS": "Etch"},{"PROCESS": "Etch"},{"PROCESS": "Etch"},{"PROCESS": "Etch"},{"PROCESS": "Etch"},{"PROCESS": "Etch"},{"PROCESS": "Etch"},{"PROCESS": "Etch"},{"PROCESS": "Etch"},{"PROCESS": "Etch"},{"PROCESS": "Etch"},{"PROCESS": "Etch"},{"PROCESS": "Etch"},{"PROCESS": "Etch"}],
    "run 2": [{"PROCESS": "Depo"},{"PROCESS": "Depo"},{"PROCESS": "Depo"},{"PROCESS": "Depo"},{"PROCESS": "Depo"},{"PROCESS": "Depo"},{"PROCESS": "Depo"},{"PROCESS": "Depo"},{"PROCESS": "Depo"},{"PROCESS": "Depo"},{"PROCESS": "Depo"},{"PROCESS": "Depo"},{"PROCESS": "Depo"},{"PROCESS": "Depo"},{"PROCESS": "Depo"}],
    "run 3": [{"PROCESS": "Etch"},{"PROCESS": "Etch"},{"PROCESS": "Etch"},{"PROCESS": "Etch"},{"PROCESS": "Etch"}]
}

它会是这样的：

我只是不确定如何将其放入 python 逻辑中。我还是新手。

这是我到目前为止所拥有的：

prev_process = ""
counter = 0
new_dict_list = {}

for dictionary in dict_list:
  if dictionary["PROCESS"] != prev_process:
    counter += 1
    prev_process = dictionary["PROCESS"]
  new_dict_list["run " + counter] = dictionary

我觉得那里应该有一个 while 循环，“while dictionary["PROCESS"] 保持不变，做一些事情”，但我不知道如何将它放入 python，或者如何突破（因为条件如果我像现在一样检查它，那将永远是正确的）。

标签： pythonlistdictionary

解决方案

您可以使用itertools.groupby：

import itertools
dict_list = [{"PROCESS": "Etch"},{"PROCESS": "Etch"},{"PROCESS": "Etch"},{"PROCESS": "Etch"},{"PROCESS": "Etch"},{"PROCESS": "Etch"},{"PROCESS": "Etch"},{"PROCESS": "Etch"},{"PROCESS": "Etch"},{"PROCESS": "Etch"},{"PROCESS": "Etch"},{"PROCESS": "Etch"},{"PROCESS": "Etch"},{"PROCESS": "Etch"},{"PROCESS": "Etch"},{"PROCESS": "Depo"},{"PROCESS": "Depo"},{"PROCESS": "Depo"},{"PROCESS": "Depo"},{"PROCESS": "Depo"},{"PROCESS": "Depo"},{"PROCESS": "Depo"},{"PROCESS": "Depo"},{"PROCESS": "Depo"},{"PROCESS": "Depo"},{"PROCESS": "Depo"},{"PROCESS": "Depo"},{"PROCESS": "Depo"},{"PROCESS": "Depo"},{"PROCESS": "Depo"},{"PROCESS": "Etch"},{"PROCESS": "Etch"},{"PROCESS": "Etch"},{"PROCESS": "Etch"},{"PROCESS": "Etch"}]
new_d = {'run {}'.format(i):list(b) for i, [_, b] in enumerate(itertools.groupby(dict_list, key=lambda x:x["PROCESS"]), 1)}

输出：

{'run 1': [{'PROCESS': 'Etch'}, {'PROCESS': 'Etch'}, {'PROCESS': 'Etch'}, {'PROCESS': 'Etch'}, {'PROCESS': 'Etch'}, {'PROCESS': 'Etch'}, {'PROCESS': 'Etch'}, {'PROCESS': 'Etch'}, {'PROCESS': 'Etch'}, {'PROCESS': 'Etch'}, {'PROCESS': 'Etch'}, {'PROCESS': 'Etch'}, {'PROCESS': 'Etch'}, {'PROCESS': 'Etch'}, {'PROCESS': 'Etch'}], 
 'run 2': [{'PROCESS': 'Depo'}, {'PROCESS': 'Depo'}, {'PROCESS': 'Depo'}, {'PROCESS': 'Depo'}, {'PROCESS': 'Depo'}, {'PROCESS': 'Depo'}, {'PROCESS': 'Depo'}, {'PROCESS': 'Depo'}, {'PROCESS': 'Depo'}, {'PROCESS': 'Depo'}, {'PROCESS': 'Depo'}, {'PROCESS': 'Depo'}, {'PROCESS': 'Depo'}, {'PROCESS': 'Depo'}, {'PROCESS': 'Depo'}], 
 'run 3': [{'PROCESS': 'Etch'}, {'PROCESS': 'Etch'}, {'PROCESS': 'Etch'}, {'PROCESS': 'Etch'}, {'PROCESS': 'Etch'}]
}

itertools.groupby根据单个键对数据进行分类。在这种情况下，数据围绕'PROCESS'键的值进行分组，从而生成嵌套列表，其中包含键值以及具有匹配键值的所有元素。创建自定义'run {number}'键，enumerate用于以干净的方式跟踪当前的迭代索引。

推荐阅读