python - 打印所有三或五的倍数的数字的总和的逻辑错误

Question

我的程序有一些逻辑错误。在过去的几个小时里，我一直在尝试解决这个问题。它应该打印所有三或五的倍数的数字的总和。

我的输出

1.)enter an integer number (0 to end): enter an integer number (0 to end):
2.)enter an integer number (0 to end): 3+ = 3

预期产出

1.)enter an integer number (0 to end): 3 = 3
2.)enter an integer number (0 to end): 3+5 = 8

下面是我的代码。

while True:
  answer = ""
  num = int(input("enter an integer number (0 to end): "))
  end_answer = 0

  if num == 0:
    exit()

  for i in range(1, num+1):
    if i%3==0 or i%5==0 :
      answer += str(i)
      end_answer += i


    if i != num and (i%3==0 or i%5==0):
      answer += "+"
      print(str(answer) + " = " + str(end_answer) )

我已经看到了类似的答案，只是没有专门在 python 中

标签： pythonpython-3.xlogic

Answer 1

以下（正确缩进）代码将为您提供所需的内容：

while True:
    num = int(input('Enter an integer number (0 to end): '))
    if num == 0: exit()

    answer = ''
    end_answer = 0
    sep = ''
    for i in range(1, num+1):
        if i % 3 == 0 or i % 5 == 0 :
            answer += sep + str(i)
            sep = ' + '
            end_answer += i

    if end_answer > 0:
        print(str(answer) + ' = ' + str(end_answer) )

请注意，它使用变量分隔符sep来更清晰地打印您正在处理的项目。示例运行如下：

Enter an integer number (0 to end): 2
Enter an integer number (0 to end): 3
3 = 3
Enter an integer number (0 to end): 10
3 + 5 + 6 + 9 + 10 = 33
Enter an integer number (0 to end): 38
3 + 5 + 6 + 9 + 10 + 12 + 15 + 18 + 20 + 21 + 24 + 25 + 27 + 30 + 33 + 35 + 36 = 329
Enter an integer number (0 to end): 0