java - 在一行中绘制多个矩形

Question

我正在尝试制作一个游戏，如果球击中一个矩形，矩形的值会下降，一旦达到 0，它就会消失。我还没有实现计数变量，但遇到了一个问题，我正在尝试沿顶部呈现数组列表，但是当我尝试绘制多个矩形并让它们留在那里时，我的循环只呈现一个对象球可以与之反应。我该怎么做？

package graphics;

import java.awt.Color;
import java.awt.Dimension;
import java.awt.Graphics;

public class Ballz extends LASSPanel
{
//Variables for the circle (Global Variables)

int circleX, circleY, circleSize;
double ballDirection,circleDX, circleDY;


//Colors
Color circleColor;
Color backgroundColor;
Dimension size;

int turn = 1;
int click =0;
int go =0;
int move = 0;
boolean roundEnd;



//Variables for the map
int brickWH;
int[] rect = new int[12];



public Ballz()
{
    //Ball Variables
    size = new Dimension(0,0);


    circleX = 190;
    circleY = 545;
    circleDX = 0;
    circleDY=0;

    circleSize = 15;

    circleColor = new Color (245,245,245);
    backgroundColor = new Color (28,28,28);

    //Game Variables
    roundEnd = true;

    brickWH = 18;
}

public void update()
{
    //Get size of screen
    getSize(size);




    circleX += circleDX;
    circleY += circleDY;



    //Screen borders
    if (circleX >= (size.width) - circleSize)
    {
        circleDX = -circleDX;
        circleX = size.width-circleSize;

    }
    if (circleX <= 0)
    {
        circleDX = -circleDX;
        circleX = 0;
    }
    if (circleY >= (size.height -circleSize))
    {
        circleDX =0;
        circleDY = 0;
        circleX = 190;
        circleY = 545;
        roundEnd = true;
    }
    if (circleY <= 0)
    {
        circleDY = -circleDY;
        circleY = 0;
    }


    circleX += circleDX;
    circleY += circleDY;


    click = getMouseButton(0);

    if (click ==1)
    {
        circleDY = -5;
        circleDX = -3;
    }


    //Rectangle Loop


    for (int i =0; i<rect.length; i++)
    {
        rect[i] = rect[i] +50;
    }





    repaint();

}

public void paint(Graphics g)
{


    //Game Colors
    g.setColor(circleColor);
    g.fillOval(circleX, circleY, circleSize, circleSize);


    for (int i=0; i<rect.length; i++)
    {
        g.fillRect(rect[i], 2, brickWH, brickWH);

    }

    setBackground(backgroundColor); 







}

}

标签： javajframedrawrect

Answer 1

好的，看到更多代码后，让我们从...

int[] rect = new int[12];

这将创建一个ints 数组，该数组最初初始化为所有0s

接下来，你做...

for (int i =0; i<rect.length; i++)
{
    rect[i] = rect[i] +50;
}

所有这一切基本上都是在添加并将50其0分配回数组元素，所以当你这样做时......

for (int i=0; i<rect.length; i++)
{
    g.fillRect(rect[i], 2, brickWH, brickWH);

}

它只是在最后一个上绘制每个“砖”，因为它们都处于相同的水平位置

真正，真的，真的，让我印象深刻的是……

for (int i =0; i<rect.length; i++)
{
    rect[i] = rect[i] +50;
}

您是否打算将每块砖相隔 50 像素？在这种情况下，您可能应该做更多类似...

int xPos = 0;
for (int i =0; i<rect.length; i++)
{
    rect[i] = xPos;
    xPos += 50;
}

相反，如果它们应该放在一起，那么你会想要更像......

for (int i =0; i<rect.length; i++)
{
    rect[i] = brickWH * i;
}