首页 > 解决方案 > 如何拆分 CSV 文件

问题描述

"0.0.0.0,""0.255.255.255"",""ZZ"""                
"1.0.0.0,""1.0.0.255"",""AU"""
"1.0.1.0,""1.0.3.255"",""CN"""
"1.0.4.0,""1.0.7.255"",""AU"""
"1.0.8.0,""1.0.15.255"",""CN"""
"1.0.16.0,""1.0.31.255"",""JP"""
"1.0.32.0,""1.0.63.255"",""CN"""
"1.0.64.0,""1.0.127.255"",""JP"""
"1.0.128.0,""1.0.255.255"",""TH"""
"1.1.0.0,""1.1.0.255"",""CN"""
"1.1.1.0,""1.1.1.255"",""AU"""
"1.1.2.0,""1.1.63.255"",""CN"""
"1.1.64.0,""1.1.127.255"",""JP"""
"1.1.128.0,""1.1.255.255"",""TH"""

优秀

0.0.0.0,"0.255.255.255","ZZ"
1.0.0.0,"1.0.0.255","AU"
1.0.1.0,"1.0.3.255","CN"
1.0.4.0,"1.0.7.255","AU"
1.0.8.0,"1.0.15.255","CN"
1.0.16.0,"1.0.31.255","JP"
1.0.32.0,"1.0.63.255","CN"
1.0.64.0,"1.0.127.255","JP"
1.0.128.0,"1.0.255.255","TH"
1.1.0.0,"1.1.0.255","CN"
1.1.1.0,"1.1.1.255","AU"
1.1.2.0,"1.1.63.255","CN"
1.1.64.0,"1.1.127.255","JP"
1.1.128.0,"1.1.255.255","TH"
1.2.0.0,"1.2.2.255","CN"
1.2.3.0,"1.2.3.255","AU"
1.2.4.0,"1.2.127.255","CN"
1.2.128.0,"1.2.255.255","TH"
1.3.0.0,"1.3.255.255","CN"
1.4.0.0,"1.4.0.255","AU"
1.4.1.0,"1.4.127.255","CN"
1.4.128.0,"1.4.255.255","TH"

如何拆分此 CSV 文件。

例如0.0.0.0 0.255.255.255 ZZ对于第一行以及如何使用 3columns 添加 datagridview

标签: c#csvsplit

解决方案


一个CSV文件要么是一个文件,要么是Tab delimited一个Comma delimited文件。那就是说;delimiter您必须逐行读取文件,然后根据字符分隔一行中可用的值。通常出现在CSV文件中的第一行通常是标题,您可以使用这些标题来生成一KeyValue对以使您的收藏更有效率。例如:

 Dictionary<int, Dictionary<String, String>> values = new Dictionary<int, Dictionary<String,String>>();
 using(FileStream fileStream = new FileStream(@"D:\MyCSV.csv", FileMode.Open, FileAccess.Read, FileShare.Read)) {
     using(StreamReader streamReader = new StreamReader(fileStream)){
          //You can skip this line if there is no header
          // Then instead of Dictionary<String,String> you use List<String>
          var headers = streamReader.ReadLine().Split(',');
          String line = null;
          int lineNumber = 1;
          while(!streamReader.EndOfStream){
               line = streamReader.ReadLine().split(',');
               if(line.Length == headers.Length){
                   var temp = new Dictionary<String, String>();
                   for(int i = 0; i < headers.Length; i++){
                      // You can remove '"' character by line[i].Replace("\"", "") or through using the Substring method
                      temp.Add(headers[i], line[i]);
                   }
                   values.Add(lineNumber, temp);
               }
               lineNumber++;
          }              
     }

如果你的数据结构CSV是不变的,以后不会改变,你可以开发一个强类型的数据模型,去掉Dictionary类型。这种方法将更加优雅和高效。


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